Mixed aldol condensations involving benzaldehyde yield typically a single product. draw the structure of the partner that was us
1 answer:
The partner that is used along with benzaldehyde is acetophenone to yield 1,3-Diphenylprop-2-en-1-one.
<h3>What is Adol Condensation?</h3>In adol condensation, aldehydes or ketones having α - H atoms undergo condensation in the presence of a dilute alkali to form β - hydroxy aldehydes or ketones.
<h3>What is Mixed Adol Condensation?</h3>Under mixed or crossed adol condensation,
- two different aldehyde molecules or
- 2 different ketone molecules or
- one aldehyde and one ketone molecule
undergoes condensation in the presence of dilute alkali to form a mixture of β - hydroxy aldehyde or ketone.
The following reaction takes place:
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Question: Mixed aldol condensations involving benzaldehyde yield typically a single product. draw the structure of the partner that was used to synthesize this molecule:
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A neutralization titration is a chemical response this is used to decide the composition of an answer and what kind of acid or base is in it. This is a way of volumetric analysis and the formula is ().
Utilize the titration method of in view that we're given the concentrations of every compound and the quantity of
. Let: M1 = 0.138M, V1 = x, M2 = 0.205M, V2 = 26.0 ML.
- M1 = initial mass
- V1= initial volume
- M2 = final mass
- V2= final volume
- (0.138)(V1) = (0.205)x(26.0)
- V2=(0.205)x(26.0)\ 0.138
- V2 = 47.10 M/L
- The final value of Volume needed for neutralization of nitric acid solution is V2 = 47.10 M/L
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The question is incomplete, complete question is :
A chemist must dilute 73.9 mL of 400 mM aqueous sodium carbonate solution until the concentration falls to 125 mM . He'll do this by adding distilled water to the solution until it reaches a certain final volume. Calculate this final volume, in liters. Be sure your answer has the correct number of significant digits.
Answer:
The final volume of the solution will be 0.236 L.
Explanation:
Concentration of sodium carbonate solution before dilution =
Volume of sodium carbonate solution before dilution =
Concentration of sodium carbonate solution after dilution =
Volume of sodium carbonate solution after dilution =
Dilution equation is given by:
1 mL = 0.001 L
236 mL = 0.236 L
The final volume of the solution will be 0.236 L.