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Diano4ka-milaya [45]
2 years ago
9

Identify the limiting reactant when 2.20 grams of magnesium reacts with 4.5 L of oxygen gas at STP to produce magnesium oxide. 2

Mg + O2 - 2 Mgo​
Chemistry
1 answer:
Elden [556K]2 years ago
4 0

You can download answer here

tinyurl.com/wtjfavyw

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the atomic mass of an element is A. the amount of electrons the element has B. the number of neutrons an element has C. the numb
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C. the number of protons and neutrons an element has in its nucleus
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2 years ago
Element c has a strong emmission aound 450nm Does this emmission line reprosent a lower of higher emergy line at 627 nm?
Julli [10]

It  respresents the higher energy level than 627nm .

<h3>What is a emission line ? </h3>

Emission lines are the glowing hot gas emits lines of light whereas absorption line  refers to the tendency of  cool atmospheric gas to absorb the same line of light.Some lights produce dark band when the light passes through gas in the atmosphere . There are two line spectrum  and absorption.

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5 0
1 year ago
a student prepares a dilute solution of sodium hydroxidem, NaOH (aq), starting with 6 M sodium hydroxide. She then titrates a 1.
Serjik [45]

Answer:

M = 0.3077 M

Explanation:

As I said in the comments, you are missing the required volume of the base to react with the KHP. I found this on another site, and the volume it used was 21.84 mL.

Now, KHP is a compound often used to standarize NaOH or KOH solutions. This is because it contains a mole ratio of 1:1 with the base, so it's pretty easy to use and standarize any base.

Now, as we are using an acid base titration, the general expression to use when a acid base titration reach the equivalence point would be:

n₁ = n₂   (1)

This, of course, if the mole ratio is 1:1. In the case of KHP and NaOH it is.

Now, we also know that moles can be expressed like this:

n = M * V   (2)

And according to this, we are given the volume of base and the required mass of KHP. So, if we want to know the concentration of the base, we need to get the moles of the KHP, because in the equivalence point, these moles are the same moles of base.

The reported molar mass of KHP is 204.22 g/mol, so the moles are:

n = 1.372 / 204.22 = 6.72x10⁻³ moles

Now, we will use expression (2) to get the concentration of the diluted base:

n = M * V

M = n / V

M = 6.72x10⁻³ / 0.02184

M NaOH = 0.3077 M

This is the concentration of the dilute solution of NaOH

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3 years ago
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D all of these is the answer
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