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Blababa [14]
2 years ago
8

Round off 0.0008769 to three significant digits.

Chemistry
1 answer:
garik1379 [7]2 years ago
6 0
8.769 x 10^-4
it will be your answer
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How many milliliters of .085 m naoh are required to titrate 25 ml of .072 m hbr to the equivalence point?
SOVA2 [1]
The ML  of 0.85  m NaOH    required   to  titrate  25 ml of  0.72m hbr  to  the  equivalence  point  is calculated  as  follows

calculate  the moles  of HBr used

moles  = molarity  x  volume

25  x0.072/1000=  0.0018 moles


write the  equation  for  reaction

NaOH + HBr = NaBr  +  H2O
from   reacting   equation the  mole ratio  between  NaOH  to  HBr  is  1:1  therefore  the  moles of  NaOH  =  0.0018 moles

volume   =  moles/molarity
0.0018/0.085 =  0.021  L  in Ml  =  0.021  x1000=21.18 Ml  ofNaOH

8 0
3 years ago
If you have 60 grams of MgCl2 in 5 liters of solution, what is the molarity of this solution?
AnnyKZ [126]

Answer:

molarity =gram/litre

=60/5

12

6 0
3 years ago
When a compound donates (loses) electrons, that compound becomes oxidized. Such a compound is often referred to as an electron d
rjkz [21]

Assuming this is a true or false question, the answer would be True

3 0
2 years ago
A sample of a gas at 25°C has a volume of 150 mL when its pressure is 0.947 atm. What will the temperature of the gas be at a pr
dezoksy [38]

Answer:

25°C

Explanation:

Combined Gas Law (P₁V₁)/T₁ = (P₂V₂)/T₂

(0.947 atm)(150 mL)/25°C = (0.987 atm)(144mL)/T₂

5.682 = 142.128/T₂

T₂ = 142.128/5.682

T₂ = 25.0137272756°C = 25°C

6 0
2 years ago
At a particular temperature, K 3.39 for the reaction SO2(9) + NO2(9) SOs(9) +NO(9) If all four gases had initial concentrations
Korvikt [17]

Answer:

The equilibrium concentrations are:

[SO2]=[NO2] =  0.563 M

[SO3]=[NO] =  1.04 M

Explanation:

<u>Given:</u>

Equilibrium constant K = 3.39

[SO2] = [NO2] = [SO3] = [NO] = 0.800 M

<u>To determine:</u>

The equilibrium concentrations of the above gases

Calculation:

Set-up an ICE table for the given reaction

         SO2(g) + NO2(g)\rightleftharpoons  SO3(g) + NO(g)

I                0.800      0.800                                  0.800       0.800

C                -x               -x                                         +x             +x

E              (0.800-x)   (0.800-x)                             (0.800+x)   (0.800+x)

The equilibrium constant is given as:

Keq = \frac{[SO3][NO]}{[SO2][NO2]}=\frac{(0.800+x)^{2}}{(0.800-x)^{2}}

3.39=\frac{(0.800+x)^{2}}{(0.800-x)^{2}}

x = 0.2368 M

[SO2]=[NO2] = 0.800 -x = 0.800 - 0.2368 = 0.5632 M

[SO3]=[NO] = 0.800 +x = 0.800 + 0.2368 = 1.037 M

4 0
2 years ago
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