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2 years ago

Round off 0.0008769 to three significant digits.

Chemistry

1 answer:

garik1379 [7]2 years ago

6 0

8.769 x 10^-4
it will be your answer

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How many milliliters of .085 m naoh are required to titrate 25 ml of .072 m hbr to the equivalence point?

SOVA2 [1]

The ML of 0.85 m NaOH required to titrate 25 ml of 0.72m hbr to the equivalence point is calculated as follows

calculate the moles of HBr used

moles = molarity x volume

25 x0.072/1000= 0.0018 moles

write the equation for reaction

NaOH + HBr = NaBr + H2O
from reacting equation the mole ratio between NaOH to HBr is 1:1 therefore the moles of NaOH = 0.0018 moles

volume = moles/molarity
0.0018/0.085 = 0.021 L in Ml = 0.021 x1000=21.18 Ml ofNaOH

8 0

3 years ago

If you have 60 grams of MgCl2 in 5 liters of solution, what is the molarity of this solution?

AnnyKZ [126]

Answer:

molarity =gram/litre

=60/5

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3 years ago

When a compound donates (loses) electrons, that compound becomes oxidized. Such a compound is often referred to as an electron d

rjkz [21]

Assuming this is a true or false question, the answer would be True

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2 years ago

A sample of a gas at 25°C has a volume of 150 mL when its pressure is 0.947 atm. What will the temperature of the gas be at a pr

dezoksy [38]

Answer:

25°C

Explanation:

Combined Gas Law (P₁V₁)/T₁ = (P₂V₂)/T₂

(0.947 atm)(150 mL)/25°C = (0.987 atm)(144mL)/T₂

5.682 = 142.128/T₂

T₂ = 142.128/5.682

T₂ = 25.0137272756°C = 25°C

6 0

2 years ago

At a particular temperature, K 3.39 for the reaction SO2(9) + NO2(9) SOs(9) +NO(9) If all four gases had initial concentrations

Korvikt [17]

Answer:

The equilibrium concentrations are:

[SO2]=[NO2] = 0.563 M

[SO3]=[NO] = 1.04 M

Explanation:

<u>Given:</u>

Equilibrium constant K = 3.39

[SO2] = [NO2] = [SO3] = [NO] = 0.800 M

<u>To determine:</u>

The equilibrium concentrations of the above gases

Calculation:

Set-up an ICE table for the given reaction

$SO2(g) + NO2(g)\rightleftharpoons SO3(g) + NO(g)$

I 0.800 0.800 0.800 0.800

C -x -x +x +x

E (0.800-x) (0.800-x) (0.800+x) (0.800+x)

The equilibrium constant is given as:

$Keq = \frac{[SO3][NO]}{[SO2][NO2]}=\frac{(0.800+x)^{2}}{(0.800-x)^{2}}$

$3.39=\frac{(0.800+x)^{2}}{(0.800-x)^{2}}$

x = 0.2368 M

[SO2]=[NO2] = 0.800 -x = 0.800 - 0.2368 = 0.5632 M

[SO3]=[NO] = 0.800 +x = 0.800 + 0.2368 = 1.037 M

4 0

2 years ago