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8090 [49]
3 years ago
7

Fluorine gas is placed in contact with calcium metal at high temperatures to produce calcium fluoride powder. What is the formul

a equation for this reaction?
Chemistry
2 answers:
yuradex [85]3 years ago
4 0

The formula equation for any reaction is the chemical equation which involves the chemical formulas of the element(s) or compound(s) involved in the reaction. On the left side of the \rightarrow, reactants are written and different reactants are separated by + sign whereas on the right side of the \rightarrow, products are written and different products are separated by + sign. The phases (solid, liquid, or gas) of all the reactants and products are written in brackets after the chemical formula of respective reactants and products.

The formula for fluorine gas is F_2 (g), acts as reactant.

The formula for calcium metal is Ca(s), acts as reactant.

The formula for calcium fluoride is CaF_2 (s), acts as product.

The reaction is written as:

F_2 (g) + Ca (s) \rightarrow CaF_2 (s)

Hence, the formula equation for the reaction is:

F_2 (g) + Ca (s) \rightarrow CaF_2 (s)

deff fn [24]3 years ago
4 0
F2 (g) + 2Ca (s) = 2CaF (s)
i hope this helps!
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5.26 grams of Ca atoms to moles.
Evgen [1.6K]

Answer:

0.131 moles.

Explanation:

moles=mass ÷ molar mass

8 0
4 years ago
Which property does a metal with a large number of free-flowing electrons most likely have?
Akimi4 [234]

a metal with a large number of free-flowing electrons most likely have good conductivity

6 0
3 years ago
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If you have 250 mL of 0.75 M LINO2.<br> How many grams of this substance<br> would you have?
Vesna [10]

Mass of this substance = 9.928 g

<h3>Further explanation</h3>

Molarity is a way to express the concentration of the solution

Molarity shows the number of moles of solute in every 1 liter of solute or mmol in each ml of solution

\large{\boxed {\bold {M ~ = ~ \frac {n} {V}}}

Where

M = Molarity

n = Number of moles of solute

V = Volume of solution

So to find the number of moles can be expressed as

\boxed{\bold{n=V\times M}}

mol of substance -Lithium nitrite - LiNO₂ :

V = 250 ml = 0.25 L

M = 0.75 M

\tt n=0.25\times 0.75=0.1875

So mass of this substance -  LiNO₂ (MW=52,947 g/mol) :

\tt mass=mol\times MW\\\\mass=0.1875\times 52,947 g/mol\\\\mass=9.928~g

4 0
3 years ago
A piece of metal with a mass of 114 g was placed into a graduated cylinder that contained 25. 00 ml of water, raising the water
alexgriva [62]

The density of the metal is 6.51 g/cm3 .

<h3>What is density, for instance?</h3>

How much "stuff" is contained in a specific quantity of space is determined by its density. For instance, a block of the harder, lighter material gold (Au) will be denser than a block of the heaviest element lead (Pb) (Au). Styrofoam blocks are less dense than bricks. Mass per unit size serves as its definition.

Briefing :

mass, m = 114 g

initial volume, V1 = 25 mL

final volume, V2 = 42.5 mL

Volume of the metal piece, V = V2 - V1

                                                 = 42.5 - 25

                                                 = 17.5 mL

1 mL = 1 c.c

So, Volume of metal, V = 17.5 c.c.

Let the density of the metal is d.

density = mass / volume

         d = 114 / 17.5

            = 6.51 g/c.c

Thus, the density of metal is 6.51 g/c.c.

To know more about density visit ;

brainly.com/question/15164682

#SPJ4

3 0
1 year ago
Ultraviolet radiation and radiation of shorter wavelengths can damage biological molecules because they carry enough energy to b
Lelechka [254]

Answer:

343.98 nm is the longest wavelength of radiation with enough energy to break carbon–carbon bonds.

Explanation:

A typical carbon–carbon bond requires 348 kJ/mol=348000 J/mol

Energy required to breakl sigle C-C bond:E

E=\frac{348000 J/mol}{6.022\times 10^{23} mol^{-1}}=5.7788\times 10^{-19} J

E=\frac{h\times c}{\lambda}

where,

E = energy of photon

h = Planck's constant = 6.626\times 10^{-34}Js

c = speed of light = 3\times 10^8m/s

\lambda = wavelength of the radiation

Now put all the given values in the above formula, we get the energy of the photons.

\lambda =\frac{(6.63\times 10^{-34}Js)\times (3\times 10^8m/s)}{5.7788\times 10^{-19} J}

\lambda =3.4398\\times 10^{-7}m=343.98 nm

1 m = 10^{9} nm

343.98 nm is the longest wavelength of radiation with enough energy to break carbon–carbon bonds.

4 0
3 years ago
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