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2 years ago

I need help pls help

Mathematics

1 answer:

Andreyy892 years ago

7 0

Answer:

[?] = 4

(the complete term is $4\frac{1}{2}\ \text{cups}$ )

Step-by-step explanation:

$8\ \text{cups} - 1\frac{1}{3}\ \text{cups} - 2\frac{1}{6}\ \text{cups} = (8-1-2)\ \text{cups} + \frac{-\frac{6}{3} - 1}{6}\ \text{cups} = 5\ \text{cups} + \frac{-3}{6}\ \text{cups} = 5\ \text{cups} + \frac{-1}{2}\ \text{cups} = 4\ \text{cups} + \frac{2 - 1}{2}\ \text{cups}$

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What steps would you take to determine if these figures are similar? Check all that apply. Use a scale factor of 2. Multiply the

skad [1K]

Answer:

Well I took it"s Reflect the intermediate image. and Multiply the vertices of polygon ABCD by One-half.

Step-by-step explanation:

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3 years ago

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Jermaine has just painted a large mural. It is 8 1/2 feet wide. The wall he wants to place it on is 11 3/4 feet wide. About how

PolarNik [594]

First turn 1/2 to 2/4 so you have a common denominator.
Next turn the mixed numbers into improper fractions:
11 3/4 --> 47/4 and 8 2/4 --> 34/4
Subtract:
47/4 - 34/4 = 13/4
Divide:
13/4 = 3.25
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Hope this helps!

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3 years ago

Orbet used 24 square tiles to make a rectangle. The perimeter of the rectangle is 20 units. What would be the perimeters of the

Dmitriy789 [7]

Answer:

The perimeter of other rectangles are 50, 28, 22 units

The area of all possible rectangles are same and equals to 24 unit²

Step-by-step explanation:

Given - Orbet used 24 square tiles to make a rectangle. The perimeter of the rectangle is 20 units.

To find - What would be the perimeters of the other rectangles Orbet could make using only these 24 tiles? How do the areas of the rectangles compare?

Proof -

We know that

Are of Rectangle = Length × Breadth

And Perimeter of Rectangle = 2 (Length + Breadth )

Now,

Given that,

Orbet used 24 square tiles

And perimeter of the rectangle made = 20

So,

Possible Length of rectangle = 6

Possible breadth of Rectangle = 4

Or Vice-versa.

Total number of Rectangles possible = 4

Possibilities are - 1 × 24, 2 × 12, 3 × 8, 4 × 6

Case I :

Length of rectangle = 1

Breadth of rectangle = 24

∴ Perimeter of rectangle = 2(1 + 24) = 2(25) = 50 units

Area of rectangle = 1 × 24 = 24 unit²

Case II :

Length of rectangle = 2

Breadth of rectangle = 12

∴ Perimeter of rectangle = 2(2 + 12) = 2(14) = 28 units

Area of rectangle = 2 × 12 = 24 unit²

Case III :

Length of rectangle = 3

Breadth of rectangle = 8

∴ Perimeter of rectangle = 2(3 + 8) = 2(11) = 22 units

Area of rectangle = 3 × 8 = 24 unit²

Case IV :

Length of rectangle = 4

Breadth of rectangle = 6

∴ Perimeter of rectangle = 2(4 + 6) = 2(10) = 20 units

Area of rectangle = 4 × 6 = 24 unit²

∴ we get

The perimeter of other rectangles are 50, 28, 22 units

The area of all possible rectangles are same and equals to 24 unit²

5 0

3 years ago

The distance from Gary's school to the corner market is 47 yards.The distance to the BART station is 12 times as far How far is

andre [41]

Answer:

The distance from Gary's school to the BART station is 564 yards

Step-by-step explanation:

Let

x ----> the distance from Gary's school to the corner market

y ----> the distance from Gary's school to the BART station

we have

$x=47\ yd$

we know that

To find out the distance from Gary's school to the BART station, multiply the distance from Gary's school to the corner market by 12

$y=12x$

substitute the value of x

$y=12(47)=564\ yd$

therefore

The distance from Gary's school to the BART station is 564 yards

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3 years ago

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gayaneshka [121]

Find slope by calculating rise (change in y) over run (change in x).

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4/-4
-1

Final answer: A

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2 years ago