Oh man. Silver coating to dampen radiating heat is great but that, of course does not tell you the temperature of the fluid inside; I would definitely add a small thermostat somewhere around the exterior. that's the only improvement I would suggest, as a standard for all.
Answer:hope we can be friends
can i please get brainliest
The Milky Way Galaxy is thought to contain hundreds of millions of black holes. But only a few dozen have revealed themselves—through the x-ray glow of hot gases that surround them. Now, astronomers have found a “dark” black hole only 1000 light-years away from Earth—just down the road in galactic terms. It is the closest black hole to our planet ever found, in a star system that is visible to the naked eye. “They have good evidence,” says Todd Thompson, an astronomer at Ohio State University, Columbus. “I believe them.”
The invisible nature of most black holes frustrates astronomers, who can learn about this final stage of stellar evolution only from the few dozen that have been found heating up an “accretion disk”—swirling gas they gobble up. Recently, however, astronomers have found several naked, nonaccreting candidates, using a technique borrowed from exoplanet searches. Exoplanet hunters look for periodic shifts in the frequency of the light from stars as it moves toward and away from Earth.
Explanation:
Is found in both the living portion of our planet and the inorganic parts of the earths system
Molar mass CaCl₂ = 111.0 g/mol
number of moles:
n = mass of solute / molar mass
n = 85.3 / 111.0
n = 0.7684 moles of CaCl₂
M = n / V
0.788 M = <span>0.7684 / V
</span>
V = 0.7684 / 0.788
V = 0.97512 L
hope this helps!
For
a first-order reaction, the rate law would be expressed as:<span>
r = dC / dt = -kC
Integrating it from time zero and
the initial concentration, Co, to time, t, and the final
concentration, C. We will obtain the first-order integrated law as follows:
ln C/Co= -kt
To determine the concentration of N2O in the system at a certain time, we simply substitute the given values from the problem statement
as follows:
</span>ln C / Co = -kt<span>
ln C / 10.9 = -0.76 (9.6)
e^ln C / 10.9 = e^-0.76 (9.6)
C / 10.9 = 6.78 x 10^-4
C= 7.39 x 10^-3 m
<span>
Therefore, the concentration of N2O in the system after 9.6 s would be 7.39 x10^-3 m.
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