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VMariaS [17]
3 years ago
12

These little bunnies (A, B, and C) were born in the same litter to the same parents, but they have different traits for the feat

ure of ear thickness. Bunny A has thick ears, bunny B has average ears, and bunny C has thin ears. How did these bunnies end up with ear thicknesses that are different from one another even though they have the same parents?
Chemistry
1 answer:
marta [7]3 years ago
3 0

Answer:

Due to random assortment and incomplete dominance of alleles.

Explanation:

The bunnies end up with ear thicknesses that are different from one another due to random assortment of alleles during gamete formation according to Mendel.

In addition to random assortment, the allele for thick ear also displayed what is known as incomplete dominance over the allele for thin ear to arrive at an average ear thickness.

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First, you need to find:
One mole of CaCl_{2} is equivalent to how many grams?

Well, for this you have to look up the periodic table. According to the periodic table:
The atomic mass of Calcium Ca = 40.078 g (See in group 2)
The atomic mass of <span>Chlorine Cl = 35.45 g (See in group 17)
</span>
As there are two atoms of Chlorine present in CaCl_{2}, therefore, the atomic mass of CaCl_{2} would be:

Atomic mass of CaCl_{2}  = Atomic mass of Ca + 2 * Atomic mass of Cl

Atomic mass of CaCl_{2} = 40.078 + 2 * 35.45 = 110.978 g

Now,

110.978 g of CaCl_{2} = 1 mole.
75.9 g of CaCl_{2} = \frac{75.9}{110.978} moles = 0.6839 moles.

Hence,
The total number of moles in 75.9g of CaCl_{2} = 0.6839 moles

According to <span>Avogadro's number,
1 mole = 1 * </span>6.022 * 10^{23} molecules
0.6839 moles = 0.6839 * 6.022 * 10^{23} molecules = 4.118*10^{23} molecules

Ans: Number of molecules in 75.9g of  CaCl_{2} =  4.118*10^{23} molecules

-i


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