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scZoUnD [109]
3 years ago
9

he electrical leads from the Constant Current System are damaged slightly, leading to a small "short-circuit" that results in 10

% of the measured current passing through the short circuit without going through the metal strips. The current displayed (and hence the value of the integral) are based on the total current, but only 90% of this actually leads to dissolution of metal. What effect would this have on your experimental value of Avogadro's Number? (Note that you complete your calculations assuming that 100% of the current is applied to dissolving the metal strip.)
Chemistry
1 answer:
VikaD [51]3 years ago
8 0

Answer:

The Avogadro's Number will reduce in value

Explanation:

From the question we are told that

The current pass through the short circuit is 0.1 *I

Here I is the total current

Generally Avogadro's Number is mathematically represented as

N_A =  \frac{Q}{ 2 *  n * e}

Here Q is the charge which is mathematically represented as

Q =  It

        n  is number of moles

        e is the charge on an electron

 So

       N_A =  \frac{I * t }{ 2 *  n * e}

Now when the current decreases from 100% to  90% due to the short circuit . this will also reduce  the no of moles of metal  dissolved hence from the equation we see that the Avogadro's Number will reduce

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Which gas law (choices are Charles' Law, Gay-Lussac's Law, or Boyle's Law) explains each scenario:________.
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Answer:

A.  Boyle's Law

B.  Charles' Law

C. Gay-Lussac's Law

Explanation:

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4 0
3 years ago
For a phase change, H0 = 2 kJ/mol and A S0 = 0.017 kJ/(K•mol). What are
34kurt

Answer:

ΔG = -6.5kJ/mol at 500K

Explanation:

We can find ΔG of a reaction using ΔH, ΔS and absolute temperature with the equation:

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Replacing:

ΔG = 2kJ/mol - 500K*0.017kJ/(K•mol)

ΔG = 2kJ/mol - 8.5kJ/mol

<h3>ΔG = -6.5kJ/mol at 500K</h3>

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