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mixas84 [53]
3 years ago
5

Which of the following is an organic compound?

Chemistry
2 answers:
Vadim26 [7]3 years ago
5 0
Most of organic compounds consists of C and H atoms. Hence <span>C. octane (C8H18) is the correct option.</span>
hram777 [196]3 years ago
4 0
I think the correct answer from the choices listed above is option C. It would be octane that is an organic  compound. <span>They are, any of a large class of chemical compounds in which one or more atoms of </span>carbon <span>are covalently linked to atoms of other elements, most commonly </span>hydrogen<span>, </span>oxygen<span>, or </span>nitrogen<span>.</span>
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p=m/v

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What is the name of this compound?
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3 years ago
What is the freezing point of an aqueous solution that has 25.00 g of calcium iodide dissolved in 1250 g of water?
ozzi

Answer:

<u></u>

  • <u>- 0.380ºC</u>

Explanation:

The lowering of the freezing point of a solvent is a colligative property ruled by the formula:

  • \Delta T_f=K_f\times m\times i

Where:

  • ΔTf is the lowering of the freezing point
  • Kf is the molal freezing constant of the solvent: 1.86 °C/m
  • m is the molality of the solution
  • i is the van't Hoff factor: the number of particles (ions) per unit of ionic compound.

<u />

<u>a) molality, m</u>

  • m = number of moles of solute/ kg of solvent
  • number of moles of CaI₂ = mass in grams/ molar mass
  • number of moles of CaI₂ = 25.00g / 293.887 g/mol = 0.0850667mol
  • m = 0.0850667mol/1.25 kg = 0.068053m

<u>b) i</u>

  • Each unit of CaI₂, ideally, dissociates into 1 Ca⁺ ion and 2 I⁻ ions. Thus, i = 1 + 2 = 3

<u />

<u>c) Freezing point lowering</u>

  • ΔTf =  1.86 °C/m × 0.068053m × 3 = 0.3797ºC ≈ 0.380ºC

<h2>I have problems to upload the full answer in here, so I attach a pdf file with the whole answer.</h2>
Download pdf
6 0
3 years ago
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