Since there are no figures given, I will give an example.
You are given a silo that is shaped as
a closed cylinder with a conical end. The diameter of the silo is 4 ft, the
length of the cylindrical part is 6 ft, and the entire length of the silo is
10.5 ft. Suppose that you are asked to find the total volume of
grains that can be stored in the silo.
Given:
Cylinder part
D = 4 ft
H = 6 ft
Cone part
H = 10.5 – 6 = 4.5ft
D = 4ft
Required:
Volume of silo
Solution:
V of cylinder = πr²H
V of cylinder = π(4/2)²(6)
V of cylinder = 75.4 ft³
V of cone = πr²H/3
V of cone = π(4/2)²(4.5/3)
V of cone = 18.85 ft³
Total volume = 94.25 ft³
Answer:
1=1=1=1=1=1=1=1=1=1=1=1=1=1=1=1=1=1=1=1=1=1-1=0
Step-by-step explanation:
The percent of change = ((new value - old value) / old value) × 100%
Our new value = $261.50
Our old value = $382
Plug our values into the equation above.
(($261.50 - $382) / $382) × 100% = -31.54%
(2/3)(30)=20
30+20=50=(x/5)
(50*5)=x=250
hope this helps
Answer: 4x+5
Step-by-step explanation:
