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2 years ago

The immediate electron acceptor for the majority of the oxidative reactions of the citric acid cycle is.

Chemistry

1 answer:

Anna [14]2 years ago

6 0

NAD serves as the bulk of the oxidative processes in the citric acid cycle's initial electron acceptor.

<h3>What are electron acceptors in citric acid cycle?</h3>

In the Krebs cycle, which transfers electrons via the electron transport chain with oxygen as the final acceptor, coenzymes like FAD and NAD+ are reduced.
In a single cycle, three NADH+ and one FADH2 are produced, and when the cycle enters the electron transport chain, 10 ATP is produced.
The final electron acceptor in the electron transport chain is oxygen. The proton gradient in the intermembrane gap is produced by NADH molecules donating electrons that are then transmitted through a number of different proteins.

<h3>What occurs throughout the citric acid cycle?</h3>

The cycle of citric acid: In the citric acid cycle, a six-carbon citrate molecule is created when an acetyl group from acetyl CoA is joined to a four-carbon oxaloacetate molecule.

Citrate is oxidized over a number of steps, generating two molecules of carbon dioxide for each acetyl group added to the cycle.

learn more about citric acid cycle here

<u>brainly.com/question/14900762</u>

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sing any data you can find in the ALEKS Data resource, calculate the equilibrium constant K at 25.0°C for the following reaction

prisoha [69]

Answer:

2.76 × 10⁻¹¹

Explanation:

I don’t have access to the ALEKS Data resource, so I used a different source. The number may be different from yours.

1. Calculate the free energy of formation of CCl₄

C(s)+ 2Cl₂(g)→ CCl₄(g)

ΔG°/ mol·L⁻¹: 0 0 -65.3

ΔᵣG° = ΔG°f(products) - ΔG°f(reactants) = -65.3 kJ·mol⁻¹

2. Calculate K

$\text{The relationship between $\Delta G^{\circ}$ and K is}\\\Delta G^{\circ} = -RT \ln K$

T = (25.0 + 273.15) K = 298.15 K

$\begin{array}{rcl}-65 300 & = & -8.314 \times 298.15 \ln K \\65300& = & 2479 \ln K\\26.34 & = & \ln K\\K& = & e^{26.34}\\&= & \mathbf{2.76 \times 10}^{\mathbf{11}}\\\end{array}$

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3 years ago

I Need Help With This I’m so Confused on it.

ss7ja [257]

Answer:

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3 years ago

For a cell whose potential is -0.46 v with 3 moles of electrons exchanged, what is DG?

Feliz [49]

ΔG = -nEF

ΔG = Gibbs free energy change
n = moles of electrones participated in
E = Electrode potential
F = Faraday constant

By substituting,
ΔG = -(3 mol) x 96485 A S/ mol x (-0.46) V
= + 133149.3 J
= + 133 kJ

Hence the answer is "b".

Since ΔG is a positive value, the reaction is non spontaneous reaction.

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3 years ago

HELP ASAP

aksik [14]

Answer:

C: Object 1 is moving, and Object 2 is not moving

Explanation:

Object one has unbalanced forces, so it can cause it to start moving ,since one force is moving stronger than its opposing one, but since Object 2 has balanced forces both forces hold it in place.

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2 years ago

A 8.95 L container holds a mixture of two gases at 21 °C. The partial pressures of gas A and gas B, respectively, are 0.373 atm

Amanda [17]

Answer:

The total pressure is 1.616 atm

Explanation:

First of all we say:

In a closed system, sum of partial pressures is the value for the total pressure.

In our system, we have gas A and B

Total pressure without the third gas is = 0.373 atm + 0.650 atm = 1.023 atm

As we add a third gas, with no change in volume or T°, let's find out by the Ideal Gases Law, its pressure:

P . V = n . R . T

P = ( n . R . T) / V

P = (0.220 mol . 0.082 . (273 + 21°C)) / 8.95L = 0.593 atm

273 + 21°C → Absolute value of T°

Let's sum the partial pressures, then:

0.373 atm + 0.650 atm + 0.593 atm = 1.616 atm.

It's ok to say that the total pressure was increased, because we have more gas now.

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3 years ago