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tigry1 [53]
2 years ago
10

The immediate electron acceptor for the majority of the oxidative reactions of the citric acid cycle is.

Chemistry
1 answer:
Anna [14]2 years ago
6 0

NAD serves as the bulk of the oxidative processes in the citric acid cycle's initial electron acceptor.

<h3>What are electron acceptors in citric acid cycle?</h3>
  • In the Krebs cycle, which transfers electrons via the electron transport chain with oxygen as the final acceptor, coenzymes like FAD and NAD+ are reduced.
  • In a single cycle, three NADH+ and one FADH2 are produced, and when the cycle enters the electron transport chain, 10 ATP is produced.
  • The final electron acceptor in the electron transport chain is oxygen. The proton gradient in the intermembrane gap is produced by NADH molecules donating electrons that are then transmitted through a number of different proteins.
<h3>What occurs throughout the citric acid cycle?</h3>

The cycle of citric acid: In the citric acid cycle, a six-carbon citrate molecule is created when an acetyl group from acetyl CoA is joined to a four-carbon oxaloacetate molecule.

Citrate is oxidized over a number of steps, generating two molecules of carbon dioxide for each acetyl group added to the cycle.

learn more about  citric acid cycle here

<u>brainly.com/question/14900762</u>

#SPJ4

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Mkey [24]

Answer:

0.109 g.

Explanation:

Equation of the reaction:

Na3PO4 + 3HCl --> 3NaCl + H3PO4

Number of moles of HCl = molar concentration × volume

= 0.1 × 0.04

= 0.004 mol.

By stoichiometry, 1 mole of Na3PO4 neutralises 3 moles of HCl. Therefore, number of moles of Na3PO4 = 0.004/3

= 0.0013 mol

Mass of Na3PO4 = molar mass × number of moles

= 0.0013 × 164

= 0.219 g

Since 50% of Na3PO4 was present in the sample. Let 100 g be the total mass of the substance

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3 years ago
A student runs an experiment in the lab and then uses the data to prepare an Arrhenius plot of the natural log of the rate const
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Applying the equation if a straight line, y=mx +c, and comparing the given equation with the graphical form of the Arrhenius equation shown in the image attached, we obtain the activation energy of the reaction as shown.

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Iteru [2.4K]
I actually don’t know but good question
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