Answer:
-586.56 kJ/mol is the standard enthalpy of the 3rd reaction.
Explanation:
...[1]
...[2]
..[3]
The unknown standard enthalpy of third reaction can be calculated by using Hess's law:
The law states that 'the heat absorbed or evolved in a given chemical equation is the same whether the process occurs in one step or several steps'.
[2] - 2 × [1] = [3]



The standard enthalpy of the 3rd reaction is -586.56 kJ/mol.The negative sign indicates that energy is released during this reaction.
N= g/m therefore g=n*m so you do...
G = 6 * (Molar mass of H2O )
G = 6 * (1.01 x 2)+(16)
G = 6 * (18.02)
G = 108.12 grams of H2O
Answer:
kci represents the formula of salt
Answer:
no. of moles = measured mass of substance/ molar mass of the constituted elements
Explanation:
No. of moles of 2.0g NaCl= 2/(23+35.5) = 0.034mol