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Marrrta [24]
3 years ago
14

1. Which curve or point of a phase diagram would indicate the melting point at various temperatures and pressures?

Chemistry
2 answers:
Flura [38]3 years ago
7 0
I think the correct answer from the choices listed above is the second option. It is the fusion curve that <span>would indicate the melting point at various temperatures and pressures. It is the boundary in the phase diagram that separates the solid and the liquid phase. </span>
yanalaym [24]3 years ago
3 0
Which curve or point of a phase diagram would indicate the melting point at various temperatures and pressures?

fusion curve

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Balanced equations account for the conservation of mass? TRUE OR FALES??
Kitty [74]
Its true, because it does balance the equations account for the conversation of the mass.
5 0
3 years ago
Read 2 more answers
PLEASE HELP DUE SOON
Alona [7]

Answer:

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Explanation:

7 0
2 years ago
How many moles in 500l of ar gas?
Alex
Assuming conditions are at 25c and 1 bar 101.25 Kpa 1 mole of gas is equal to 22.4 L

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8 0
3 years ago
If 5.00 mL of 1.00 M HCl is used to titrate the hydroxide ion produced by a piece of Sodium, What mass of Sodium is used in gram
suter [353]

Answer:

Explanation:

Equation of the reaction:

NaOH + HCl --> NaCl + H2O

Volume of HCl = 5 ml

Molar concentration = 1 M

Number of moles = molar concentration * volume

= 1 * 0.005

= 0.005 mol of HCl

By stoichiometry, 1 mole of HCl completely neutralizes 1 mole of NaOH

Therefore, number of moles of NaOH = 0.005 mol

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Mass = molar mass * number of moles

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6 0
3 years ago
A gas balloon has a volume of 80.0 mL at 300K, and a pressure of 50.0 kPa. If the pressure changes to 80 kPa and the temperature
fomenos

Answer:  The new volume is 53.3 ml

Explanation:

The combined gas equation is,

\frac{P_1V_1}{T_1}=\frac{P_2V_2}{T_2}

where,

P_1 = initial pressure of gas =  50.0 kPa

P_2 = final pressure of gas = 80.0 kPa

V_1 = initial volume of gas = 80.0 ml

V_2 = final volume of gas = ?

T_1 = initial temperature of gas = 300K

T_2 = final temperature of gas = 320K

Now put all the given values in the above equation, we get:

\frac{50.0\times 80.0}{300}=\frac{80.0\times V_2}{320}

V_2=53.3ml

The new volume is 53.3 ml

4 0
3 years ago
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