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4 years ago

1. Which curve or point of a phase diagram would indicate the melting point at various temperatures and pressures?

2 answers:

7 0

I think the correct answer from the choices listed above is the second option. It is the fusion curve that <span>would indicate the melting point at various temperatures and pressures. It is the boundary in the phase diagram that separates the solid and the liquid phase. </span>

yanalaym [24]4 years ago

3 0

Which curve or point of a phase diagram would indicate the melting point at various temperatures and pressures?

fusion curve

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What is 1 mol / 66.04g

____ [38]

Answer:

15.142338 mol/kg

Explanation:

(1 mole) / (66.04 grams)

5 0

3 years ago

H2SO4 +HI → __ H2S+12 +H2O balance the equation

Citrus2011 [14]

Answer:

H2SO4 + 8HI → H2S + 4I2 + 4H2O

3 0

3 years ago

A gas mixture with 4 mol of Ar, x moles of Ne, and y moles

maks197457 [2]

Answer:

a) $\Delta G_{mixing}=\frac{R*T}{12}*[4*ln (1/3) +x*ln (x/12) +(8-x)*ln ((8-x)/12)]$

b) $x=4$

c) $\Delta G_{max}=-2721.9 J/mol$

Explanation:

Gas mixture:

$n_{Ar}= 4 mol$

$n_{Ne}= x mol$

$n_{Xe}= y mol$

$n_{tot}= n_{Ar} + n_{Ne} + n_{Xe}=3*n_{Ar}$

$n_{Ne} + n_{Xe}=2*n_{Ar}$

$x + y=8 mol$

$y=8 mol- x$

Mol fractions:

$x_{Ar}=\frac{4 mol}{12 mol}=1/3$

$x_{Ne}=\frac{x mol}{12 mol}=x/12$

$x_{Xe}=\frac{8 - x mol}{12 mol}=(8-x)/12$

Expression of $\Delta G_{mixing}$

$\Delta G_{mixing}=R*T*\sum_{i]*x_i*ln (x_i)$

$\Delta G_{mixing}=R*T*[1/3*ln (1/3) +x/12*ln (x/12) +(8-x)/12*ln ((8-x)/12)]$

$\Delta G_{mixing}=\frac{R*T}{12}*[4*ln (1/3) +x*ln (x/12) +(8-x)*ln ((8-x)/12)]$

Expression of $\Delta G_{max}$

$\frac{d \Delta G_{mixing}}{dx}=0$

$\frac{d \Delta G_{mixing}}{dx}=\frac{R*T}{12}*[ln (x/12)+12-ln ((8-x)/12)-12]$

$0=\frac{R*T}{12}*[ln (x/12)-ln ((8-x)/12)$

$0=[ln (x/12)-ln ((8-x)/12)$

$ln (x/12)=ln ((8-x)/12)$

$x=(8-x)$

$x=4$

$\Delta G_{max}=\frac{8.314*298}{12}*[4*ln (1/3) +4*ln (4/12) +(8-4)*ln ((8-4)/12)]$

$\Delta G_{max}=\frac{8.314*298}{12}*[4*ln (1/3) +4*ln (1/3) +(4)*ln (1/3)]$

$\Delta G_{max}=\frac{8.314*298}{12}*[12*ln (1/3)]$

$\Delta G_{max}=-2721.9 J/mol$

4 0

3 years ago

how many grams of oxygen gas are needed to produce 10.0 grams of carbon dioxide according to the balanced equation of CH4

Alinara [238K]

Molar mass of :

O2 = 16 * 2 = 32 g/mol

CO2 = 12 + 16 * 2 = 44 g/mol

<span>Balanced chemical equation :
</span>
1 CH4 + 2 O2 = 1 CO2 + 2 H2O
↓ ↓
2 moles 1 mole

2* 32 g O2 ----------> 1* 44 g CO2
x g O2 ------------> 10.0 g CO2

44 x = 2 * 32*10.0

44 x = 640

$x = \frac{640}{44}$

$x = 14.54 g$ of O2

7 0

3 years ago

john dalton's original atomic theory contained the following key ideas. which part(s) of these ideas was/were incorrect?

Degger [83]

John Dalton's original atomic theory contained the following key ideas and the incorrect one is that elements are made of tiny indivisible particles called atoms and is denoted as option A.

This is defined as the smallest unit of matter which forms a chemical element and Dalton proposed that it was indivisible which was later proved wrong.

It was later discovered that atom is made up of sub atomic particles such as proton, electron and neutron. This was therefore the reason why option A was chosen as the most appropriate choice.

Read more about Atom here brainly.com/question/6258301

#SPJ1

The options include:

A. elements are made of tiny indivisible particles called atoms

B. Atoms are unchanged in chemical reaction

C. Atoms can join together in whole number ratios to form compounds.

D. The atoms of each element are unique

7 0

2 years ago