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matrenka [14]
3 years ago
14

WILL MARK BRAINLIEST!! What is the percent composition of each element in barium nitrate?

Chemistry
1 answer:
11111nata11111 [884]3 years ago
8 0
<span>the percent composition of each element in barium nitrate is:</span><span>
52.56% Barium
10.71% nitrogen
36.73% oxygen

Hope this helps:)
</span>
You might be interested in
The circles, or orbits, for electrons are called energy levels. Each level can hold only a certain number of electrons. Add elec
vivado [14]

Answer: n = 1 can hold a maximum of 2 electrons

n = 2 , maximum 8 electrons

n = 3, maximum 18 electrons

As per the principles of quantum mechanics, the number of electrons that can be added to a given energy level is deduced based on the three quantum numbers: n, l , m(l) and m(s)

'n' is the principal quantum number which defines the energy level. It can take on integer values: 0,1,2,3...

'l' is the angular momentum quantum number which defines the shape of the orbital that an electron occupies

l = 0,1,2...(n-1)

where: l = 0 corresponds to s-orbital

l = 1 corresponds to p-orbital

l = 2, corresponds to d-orbital

'm(l)' is the magnetic moment quantum number which defines the orientation of an orbital  in space.

m(l) = -l, 0, +l

'm(s)' is the spin quantum number which defines the orientation of an electron is an orbital m(s) = +1/2 or -1/2

An s, p or d-orbital can accommodate a maximum of 2, 6 and 10 electrons respectively For energy level with n= 1

l = 0, i.e. s-orbital or 1s.

Therefore, the maximum number of electrons for a 1s orbital would be 2 resulting in an electron configuration of 1s²

For energy level with n= 2

l = 0, 1 i.e. s and p-orbitals

The maximum number of electrons would be

Electron configuration: 2s²2p⁶

For energy level with n= 3

l = 0, 1, 2 i.e. s, p and d-orbitals

The maximum number of electrons would be

Electron configuration: 3s²3p⁶3d¹⁰

5 0
3 years ago
If an enclosure of 0.432 L has a partial pressure of O2 of 3.4×10−6 torr at 28 ∘C, what mass of magnesium will react according t
Mama L [17]

Answer:

184620169 g.

We can say that this mass corresponds to 184.6 ton

Explanation:

This is the reaction:  2Mg (s) + O₂(g) →  2MgO (s)

We have the data of O₂, so let's find out the moles with the Ideal Gases Law.

First of all, we convert pressure to atm

760 Torr / 3.4×10⁻⁶ Torr = 223529.4 atm

P .V = n . R . T

223529.4 atm . 0.432L = n . 0.082 L.atm/mol.K . 301K

(223529.4 atm . 0.432L) / (0.082 L.atm/mol.K . 301K) = 3798769 moles

Gosh!, These are a lot of moles.

Ratio is 1:2. So with 3798769 moles we would need the double of moles of Mg. → 3798769 mol  .2  = 7597538 moles

Let's convert this moles into mass ( mol . molar mass)

7597538 mol . 24.3 g/mol = 184620169 g

We can convert this mass to ton

1 ton = 1×10⁶ g

184620169 g / 1×10⁶ g = 184.6 ton

5 0
4 years ago
HELP!!!! I WILL MARK BRAINLIEST WHOEVER ANSWERS FIRST
ELEN [110]

Answer:

I answered first, give me brainliest

Explanation:

8 0
3 years ago
A crystallographer measures the horizontal spacing between molecules in a crystal. The spacing is
Kamila [148]
That's what I was thinking. I wasn't sure if we were precisely interested in finding the molecule's width as well (which I didn't know how to do but had a vague idea of how we might accomplish it). If this is just for unit conversions though, your answer seems sufficient. You just need to convert nanometers to millimeters.
8 0
4 years ago
Why is hydrogen (H) placed with the elements in Group 1A?
Alex787 [66]
It has ns1 electron configuration like the alkali metals. 
6 0
3 years ago
Read 2 more answers
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