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2 years ago

A diverging lens has a focal length of 18.0 cm. An insect is placed 7.00 cm in front of the lens. What is the magnification

Physics

1 answer:

musickatia [10]2 years ago

3 0

Diverging lens=concave lens

The image would be after the first focal point but before the lens and it will be smaller than the object. Look at my picture for reference. Please let me know if this helped you!

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A car accelerates along a straight road from rest to 90 km/h in 5.0 s. A) Find the magnitude of its average acceleration. B) Fin

egoroff_w [7]

Answer:

a) $A=5m/s^2$

b) $V=25m/s$

Explanation:

From the question we are told that:

Velocity $v=90km/h=25m/s$

Time $t=5.0s$

Generally From Newton's motion equation for Average acceleration is mathematically given by

$A=\frac{V-U}{t}$

Since its from Rest Therefore

$U=0$

$A=\frac{25m/s-0}{5s}$

$A=5m/s^2$

Generally the equation for Average Velocity is mathematically given by

$V=u+at$

$AT t=1.0s\\\\V=0+5(1)$

$V=5m/s$

$AT t=2.0s\\\\V=0+5(2)$

$V=10m/s$

$AT t=5.0s\\\\V=0+5(5)$

$V=25m/s$

6 0

2 years ago

A running student has half the kinetic energy that his brother has. The student speeds up by 1 m/s, at which point he has the sa

hoa [83]

Answer:

V = (√2) + 1) m/s

Explanation:

Let the mass and speed of the running student be M and V respectively.

We are told that when he speeds up by 1 m/s, he has the same kinetic energy as his brother.

Thus, his speed at which he mow has the same kinetic energy as his brother is (V + 1) m/s

Now, we are told that the mass of the student is twice as large as that of his brother. Thus, his brother's mass is; M/2

Since kinetic energy is given by the formula K.E = ½mv²

Therefore, since we want to find the original speed of both students and that the initial condition says that the running student had half the kinetic energy of the brother, we now initial condition as;

½MV²= ½(½(M/2)V²) - - - - (eq 1)

Since he has sped up by 1 m/s, and has a kinetic energy now equal to that of his brother, we have;

(½M(V + 1)²) = (½(M/2)V²) - - - - (Eq2)

Dividing eq 1 by eq 2 gives;

V²/(V + 1)²= 1/2

Taking square root of both sides gives;

V/(V + 1) = 1/√2

Cross multiply to give;

(√2)V = V + 1

(√2)V - V = 1

V((√2) - 1) = 1

V = 1/((√2) - 1)

Simplifying this using surfs gives;

V = [1/((√2) - 1)] × ((√2) + 1))/((√2) + 1))

V = ((√2) + 1))/1

V = (√2) + 1) m/s

8 0

3 years ago

Physics Question: Determine the work that is being done by tension in pulling the box 193.0 cm along the table. Also determine t

lozanna [386]

1) The work done by tension is 12.0 J

2) The final speed of the box is 1.57 m/s

Explanation:

The work done by a force on an object is given by:

$W=Fd cos \theta$

where

F is the magnitude of the force

d is the displacement

$\theta$ is the angle between the direction of the force and of the displacement

For the box in this problem, we have:

F = 6.2 N is the force applied (the tension in the string)

d = 193.0 cm = 1.93 m is the displacement

$\theta=0$ assuming that the string is horizontal

Substituting, we find the work done by the tension:

$W=(6.2)(1.93)(cos 0)=12.0 J$

In order to determine the final speed of the box, we need to determine its acceleration first.

Beside the tension, acting forward, the other force acting horizontally on the box is the force of friction, whose magnitude is

$F_f = \mu mg$

where

$\mu=0.16$ is the coefficient of friction

m = 2.8 kg is the mass of the box

$g=9.8 m/s^2$ is the acceleration of gravity

Substituting,

$F_f = (0.16)(2.8)(9.8)=4.4 N$

Therefore, the net force on the box is

$F=6.2 N - 4.4 N = 1.8 N$

And the acceleration can be found by using Newton's second law:

$F=ma$

where

F = 1.8 N is the net force

m = 2.8 kg is the mass of the box

a is the acceleration

Solving for a,

$a=\frac{F}{m}=\frac{1.8}{2.8}=0.64 m/s^2$

Now we can finally find the final speed using the suvat equation:

$v^2-u^2=2as$

where

v is the final speed

u = 0 is the initial speed

$a=0.64 m/s^2$ is the acceleration

s = 1.93 m is the displacement

Solving for v,

$v=\sqrt{u^2+2as}=\sqrt{0+2(0.64)(1.93)}=1.57 m/s$

Learn more about work:

brainly.com/question/6763771

brainly.com/question/6443626

#LearnwithBrainly

3 0

3 years ago

Which of the following is an obstacle to creating computer-based models for tracking a hurricane?

AnnZ [28]

Forecasters must consider a large number of variables that affect the path of the storm.
This makes it difficult to create computer-based models because all of these variables are hard to incorporate.

5 0

2 years ago

Read 2 more answers

The transmission of heat requiring the movement of a liquid or a gas is A. transduction. B. convection. C. conduction. D. radiat

madreJ [45]

The correct answer is convection

In liquids and gases, convection is the most prominent method for the transfer of energy or heat. Convection is caused by the movement of the hotter particles to a region of colder particles takes place. This results in making the whole liquid or gas hot or warm.

Example: The water bubbles in boiling water moves from bottom to the top of the pan to cover the colder water present at the top.

This is because of convection.

8 0

3 years ago

Read 2 more answers