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Vaselesa [24]
3 years ago
14

Which two factors determine the force of gravity between two objects?

Physics
1 answer:
Mila [183]3 years ago
5 0
Distance and inertia
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If it takes an amount of work W to move two q point charges from infinity to a distance d apart from each other, then how much w
aleksklad [387]

Answer:3W

If it takes an amount of work W to move two q point charges from infinity to a distance d apart from each other, then how much work should it take to move three q point charges from infinity to a distance d apart from each other?

A) 2W

B) 3W

C) 4W

D) 6W

Explanation: calculating work done,W, in moving two positive q point charges from infinity to a valued distance d from each other  is

W = k(+q)(+q)/ d

k is couloumb's constant

work done in moving 3 equal positive charges from infinity to a finite distance is given by

W₂=W₄=W₆=k(+q)(+q)/ d

Total work done, W' =k(+q)(+q)/ d + k(+q)(+q)/ d + k(+q)(+q)/ d

= W + W + W = 3W

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3 years ago
Someone please help my universe revision!!
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In order to do work, the force vector must be
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in the same direction as the displacement vector and the motion

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3 years ago
If you increase the frequency, what happens to the velocity of the wave?
STALIN [3.7K]

Answer:

Wave frequency does not affect wave speed. An increase in wave frequency caused a decrease in wavelength while the wave speed remained constant. ... Rather, the speed of the wave is dependent upon the properties of the medium such as the tension of the rope.

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3 years ago
Two identical closely spaced circular disks form a parallel-plate capacitor. Transferring 2.1×109 electrons from one disk to the
Bad White [126]

Answer:

d = 0.018 m

Explanation:

Charge on the plates of the capacitor due to transfer of electrons is given as

Q = Ne

here we know that

N = 2.1 \times 10^9

so we have

Q = (2.1 \times 10^9)(1.6 \times 10^{-19})

Q = 3.36 \times 10^{-10} C

now we have electric field between the plates is given as

E = \frac{Q}{A\epsilon_0}

here we have

1.5 \times 10^5 = \frac{3.36 \times 10^{-10}}{A(8.85 \times 10^{-12})}

A = 2.53 \times 10^{-4} m^2

now we have

A = \frac{\pi d^2}{4}

2.53 \times 10^{-4} = \frac{\pi d^2}{4}

d = 0.018 m

3 0
3 years ago
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