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lora16 [44]
2 years ago
10

What can you conclude about the ad disease from the cd4-deficient (cd4-ko) and cd8-deficient (cd-ko) mice?

Chemistry
1 answer:
Yuki888 [10]2 years ago
6 0

CD4 and CD8 T-cell numbers are decreased after blunt trauma.

<h3>Blunt trauma</h3>

A body damage brought on by a strong collision with a dull item or surface is known as blunt trauma, also known as non-penetrating trauma or blunt force trauma. It differs from penetrating trauma, which occurs when an object or surface pierces the body and leaves an open wound. To stabilize and care for the patient, trauma hospitals need to use a coordinated, multidisciplinary approach. For instance, a Level I trauma center has well-established treatment protocols in place and specific sorts of healthcare specialists on call around-the-clock, seven days a week.

Learn more about blunt trauma here:

brainly.com/question/17986674

#SPJ4

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Alika [10]

The movement creates a difference in air pressure.

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Explanation:

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Which of the following pairs of elements is most likely to form an ionic bond? A. nitrogen and oxygen B. aluminum and nitrogen C
krok68 [10]

Answer:

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Explanation:

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\Hope i could help xxxxxxxxxxxxxxxxxxx

6 0
2 years ago
2p is the correct representation for the sub-shell with n = 2 and l = 1.
boyakko [2]

Explanation:

Principle Quantum Numbers : It describes the size of the orbital and the energy level. It is represented by n. Where, n = 1,2,3,4....

Azimuthal Quantum Number : It describes the shape of the orbital. It is represented as 'l'. The value of l ranges from 0 to (n-1). For l = 0,1,2,3... the orbitals are s, p, d, f...

s = 1 orbital

p = 3 orbitals

d = 5 orbitals

f = 7 orbitals

For n = 4

l = 0 to (n-1) = 0 to 3 = (4s , 4p , 4d , 4f)

Number of subshells = 4

Number of orbitals =         1 + 3 + 5 + 7  = 16

The maximum number of electrons the n = 4 shell can contain:

Each orbital can holds upto two electrons, then 16 orbitals will have :

16\times 2=32

32 is the maximum number of electrons the n = 4 shell can contain

6 0
3 years ago
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The equation below shows the products formed when a solution of silver nitrate (AgNO3) reacts with a solution of sodium chloride
d1i1m1o1n [39]
I would say that the answer has to be C
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3 years ago
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