Mass/volume
In order to find density, you need to divide mass/volume
Answer:
a) The mass of lead in the alloy = 0.28 kg
b) There can be dissolved 1.46 kg more of lead.
Explanation:
Step 1: Data given
mass of the magnesium-lead alloy = 5.5 kg
200 °C → 5 wt% Pb
350 °C → 25 wt% Pb
a) What mass of lead is in the alloy?
We have to calculate (for the magnesium-lead alloy) the mass of lead in 5.5 kg of the solid α phase at 200°C just below the solubility limit. The solubility limit for the α phase at 200°C is about 5 wt% Pb.
The mass of lead in the alloy = (0.05)*(5.5 kg) = 0.28 kg
b) If the alloy is heated to 350°C, how much more lead may be dissolved in the α phase without exceeding the solubility limit of this phase?
At 350°C, the solubility limit of the a phase increases to approximately 25 wt% Pb.
C(lead) = ((mass fo lead in alloy) + (mass lead)) / ((magnesium-lead alloy mass) + (mass lead))
0.25 = (0.28 + m(Pb)) / ( 5.5 + m(Pb))
0.25 * ( 5.5 + m(Pb)) = (0.28 + m(Pb))
1.375 + 0.25 m(Pb) = 0.28 + m(Pb)
1.095 = 0.75 m(Pb)
m(Pb) = 1.095 / 0.75
m(Pb) = 1.46
There can be dissolved 1.46 kg more of lead.
Answer:
wind
pollution free no use of resources
The answer is letter b. from the sunlight. Plants are also referred as producers. Typically, plants gets their energy from the sun, wherein it helps them produce their own food, through the sunlight, the carbon dioxide present, the process wherein the producers undergo is known as photosynthesis.
Answer:
The enthalpy of the reaction is -123.5 kJ.
Explanation:
..(1)
..(2)
...(3)
(2) - (1)
Dividing equation by 4 we get (3)
...(3)
The enthalpy of the reaction is -123.5 kJ.