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pogonyaev
3 years ago
5

What volume of stock solution and water must you add to prepare 36.25ml of a 1.25M solution

Chemistry
1 answer:
Serjik [45]3 years ago
5 0

Given :

Number of moles , n = 36.25 mol .

Molarity , M = 1.25 M .

To Find :

The volume of water required .

Solution :

Moarity is given by :

M=\dfrac{n}{V}

So , V=\dfrac{n}{M}

Here , n is number of moles and M is molarity .

Putting all values in above equation , we get :

V=\dfrac{36.25}{1.25}\\\\V=29\ L

Therefore , volume of water required is 29 L .

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if 11.74 liters of gas at STP are pumped into a basketball, how many moles of gas are in the basketball? assume the basketball w
ser-zykov [4K]

Answer:

0.52 mol

Explanation:

Using the general gas equation formula:

PV = nRT

Where;

P = pressure (atm)

V = volume (Liters)

n = number of moles (mol)

R = gas law constant (0.0821 Latm/molK)

T = temperature (K)

At STP (standard temperature and pressure), temperature of a gas is 273K, while its pressure is 1 atm

Using PV = nRT

n = PV/RT

n = (1 × 11.74) ÷ (0.0821 × 273)

n = 11.74 ÷ 22.41

n = 0.52 mol

There are 0.52 moles in the basketball

6 0
3 years ago
Does the identity of gas matter when predicting its behavior why or why not?
just olya [345]

Answer: The gas phase is unique among the three states of matter in that there are some simple models we can use to predict the physical behavior of all gases—independent of their identities. We cannot do this for the solid and liquid states. ... Gas particles do not experience any force of attraction or repulsion with each other.

Explanation:

4 0
3 years ago
Answer these two questions, please.
IRINA_888 [86]

Answer:

neom, sodium bicarbonate

7 0
2 years ago
A mixture of0.161 moles of C is reacted with 0.117 moles of O2 in a sealed, 10.0 L-vessel at 500.0 K, producing a mixture of CO
labwork [276]

Answer:

number of moles of CO2 is 0.054

number of moles of CO is 0.107

number of moles of O2 remaining is 0.01 mole

mole fraction of CO is 0.63

Explanation:

Firstly, we write the equation of reaction;

3C(s) +2O2(g) → CO2(g) +2CO(g)

Now, we proceed.

From the written equation, we can deduce that

3 mol C = 2 mol O2 = 1 mol CO2 = 2 mol CO

No of mol of C reacted = 0.161 mol

limiting reactant according to the question is Carbon

a. no of mol of CO2 formed = 0.161*1/3 = 0.054 moles ( no of moles of CO2 formed is one-third of no of moles of carbon reacted. This is obtainable from their mole ratio 1:3)

b. no of mol of CO formed = 0.161*2/3 = 0.107 mol

c. no of mol of O2 remaining = 0.117 - (0.151*2/3) = 0.117-0.107 = 0.01 mole

d. mole fraction of CO = no of mol of CO/Total number of moles

= 0.107/(0.107+0.054+0.01)

= 0.625730994152 which is approximately 0.63

5 0
3 years ago
Ionization energy is a measure of the ability of atoms to attract electrons within a bond. True False
Xelga [282]

Answer:

The correct option is False

Explanation:

Ionization energy is the <em>minimum amount of energy required to remove a valence electron from one mole of an atom in it's gaseous state</em>. Ionization energy requires the removal of an electron from a gaseous atom. The definition in the question is that of electronegativity.

Electronegativity is the <u>ability of an atom to attract electrons towards itself in a chemical bond.</u>

5 0
3 years ago
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