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professor190 [17]
3 years ago
11

How deep does the surface current known as the Gulf Stream go

Chemistry
2 answers:
Irina-Kira [14]3 years ago
8 0

i think its A because nobody really knows how deep it is

GuDViN [60]3 years ago
4 0

Not 100%. Sure but I’m pretty sure she’s right^

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Please helpp: All things that are acidic will eventually produce ___ in an aqueous solution?​
BARSIC [14]

Answer:

Protons / H+ ions

Explanation:

8 0
3 years ago
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A 2.5 L sample of gases at STP (standard temperature and pressure is 273 k and 1.00 atm). When the temperature is raised to 273d
podryga [215]

Answer:

x = 5.9

Explanation:

6 0
3 years ago
2HgCl2(aq) + C2O42–(aq) → 2Cl–(aq) +2CO2(g) + Hg2Cl2(s)
alexgriva [62]

Explanation:

Expression for rate of the given reaction is as follows.

             Rate = k[HgCl_{2}]x [C_{2}O^{2-}_{4}]y[/tex]

Therefore, the reaction equations by putting the given values will be as follows.

       1.8 \times 10^{-5} = k[0.105]x [0.15]y ............. (1)

       7.2 \times 10^{-5} = k [0.105]x [0.30]y ........... (2)

       3.6 \times 10^{-5} = k [0.0525]x [0.30]y ............ (3)

Now, solving equations (1) and (2) we get the value of y = 2. Therefore, by solving equation (2) and (3)  we get the value of x = 1.

Therefore, expression for rate of the reaction is as follows.

     Rate = k[HgCl_{2}]x [C_{2}O^{2-}_{4}]y

          Rate = k [HgCl2]1 [C_{2}O^{-2}_{4}]2

Hence, total order = 1 + 2 = 3

According to equation (1),

               1.8 \times 10^{-5} = k[0.105]x [0.15]y  

            1.8 \times 10^{-5} = k [0.105]1 [0.15]2  

                      k = 7.6 \times 10^{-3} M^{-2} min^{-1}  

Thus, we can conclude that rate constant for the given reaction is 7.6 \times 10^{-3} M^{-2} min^{-1}.

8 0
2 years ago
RODINNIS
Mashcka [7]

where it was formed and. conditions it was formed under

6 0
3 years ago
Which statement best describes the molecules in a solid?
malfutka [58]

Answer:hello

The third one is correct.

Explanation:

Because the molecules of solids can just have some little vibration in their places.

The first one is for gas so it's incorrect.

The second one is for liquid.

And finally the third one is correct.

Good luck.

4 0
2 years ago
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