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Bad White [126]
3 years ago
8

The volume of a gas is 5.80L, measured at 1.00atm. What is the pressure of the gas in mmHg if the volume is changed to 9.65L ( t

emperature is kept constant)
Chemistry
1 answer:
jasenka [17]3 years ago
8 0

Answer:

The new pressure is 456.76 mmHg

Explanation:

Step 1: Data given

The initial volume of the gas = 5.80 L

The initial pressure of the gas = 1.00 atm

The volume of the gas increases to 9.65 L

The temperature is kept constant

Step 2: Calculate the new pressure

P1*V1 = P2¨V2

⇒with P1 = the initial pressure of the gas = 1.00 atm

⇒with V1 = the initial volume of the gas = 5.80 L

⇒with P2 = the new pressure = TO BE DETERMINED

⇒with V2 = the increased volume of the gas = 9.65 L

1.00 atm * 5.80 L = P2 * 9.65 L

P2 = (5.80 / 9.65)

P2 = 0.6010 atm

Step 3: Convert pressure from atm to mm Hg

0.6010 atm * 760 mmHg = 456.76 mmHg

The new pressure is 456.76 mmHg

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<u>Answer:</u> The amount of carbon dioxide gas produced in the reaction is 83.6 grams

<u>Explanation:</u>

As, some amount of oxygen gas is left after the reaction is completed. So, it is present in excess and is considered as an excess reagent.

Thus, carbon is considered as a limiting reagent because it limits the formation of product.

To calculate the number of moles, we use the equation:

\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}     .....(1)

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Putting values in equation 1, we get:

\text{Moles of carbon}=\frac{22.8g}{12g/mol}=1.9mol

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By Stoichiometry of the reaction:

1 mole of carbon produces 1 mole of carbon dioxide gas

So, 1.9 moles of carbon will produce = \frac{1}{1}\times 1.9=1.9moles of carbon dioxide gas

Now, calculating the mass of carbon dioxide from equation 1, we get:

Molar mass of carbon dioxide = 44 g/mol

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Putting values in equation 1, we get:

1.9mol=\frac{\text{Mass of carbon dioxide}}{44g/mol}\\\\\text{Mass of carbon dioxide}=(1.9mol\times 44g/mol)=83.6g

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3 years ago
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Thermal energy transfers in a solid state, due to convection, in metalic substances.

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