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2 years ago

Balancing chemical equations

Chemistry

1 answer:

kolbaska11 [484]2 years ago

7 0

Answer:

2B2 + 3O2 → 2B2O3

Explanation:

Balance The Equation: B2 + O2 = B2O3

1. Label Each Compound With a Variable

aB2 + bO2 = cB2O3

2. Create a System of Equations, One Per Element

B: 2a + 0b = 2c

O: 0a + 2b = 3c

3. Solve For All Variables (using substitution, gauss elimination, or a calculator)

a = 2

b = 3

c = 2

4. Substitute Coefficients and Verify Result

2B2 + 3O2 = 2B2O3

L R

B: 4 4 ✔️

O: 6 6 ✔️

hope this helps!

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Explanation:

From the question given above, the following data were obtained:

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Answer:

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b) Solubility is 6.31x10⁻⁶M

Explanation:

a) InF₃ in water produce:

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And Ksp is defined as:

Ksp = [In⁺³] [F⁻]³

4.0x10⁻²g / 100mL of InF₃ are:

4.0x10⁻²g / 100mL ₓ (1mol / 172g) ₓ (100mL / 0.1L) = 2.3x10⁻³M InF₃. Thus:

[In⁺³] = 2.3x10⁻³M InF₃ × (1 mol In⁺³ / mol InF₃) = 2.3x10⁻³M In⁺³

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Replacing these values in Ksp formula:

Ksp = [2.3x10⁻³M In⁺³] × [7.0x10⁻³M F⁻]³ = 7.9x10⁻¹⁰

b) 0.05 moles of F⁻ produce solubility of InF₃ decrease to:

7.9x10⁻¹⁰ = [x] [0.05 + 3x]³

Where x are moles of In⁺³ produced from solid InF₃ and 3x are moles of F⁻ produced from the same source. That means x is solubility in mol / L

Solving from x:

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x = 6.31x10⁻⁶M → Right answer.

Thus, solubility is 6.31x10⁻⁶M

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