If we need our line to pass through point C, then we have to use the x and coordinates of point C in our new equation. If that line is to be perpendicular to AB, we also need to find the slope of AB and then take its opposite reciprocal. First things first. Point C lies at (6, 4) so we will use x = 6 and y = 4 in our equation in a bit. The coordinates of A are (-2, 4) and the coordinates of B are (2, -8) so the slope between them is

which is -3. The opposite reciprocal of -3 is 1/3. That's the slope we will use along with the points from C to write the new equation. We will do this by plugging in x, y, and m (slope) into the slope-intercept form of a line and solve for b.

and 4 = 2 + b. So b = 2. That's the y-intercept, the point on the y axis where the line goes through when x is 0. Therefore, the point you're looking for is (0, 2).
C, a²+b²=c²
why does this have to be 20 characters long
You just multiply the 2 numbers!
I'm so sorry but I can't help you with this problem
Answer:
(-1, -3)
Step-by-step explanation:
We suppose your notation means you want to reflect given point P across the horizontal line y=1.
The x-coordinate will remain the same.
The new y-coordinate will be such that y=1 is the midpoint between the original and its reflection:
(5 + y)/2 = 1
5 + y = 2 . . . . multiply by 2
y = 2 -5 = -3 . . . subtract 5
The reflected point is (-1, -3).
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The same sort of math applies whenever you have a midpoint and want to find the other end point. Double the midpoint value and subtract the end point you have in order to find the other end point.