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2 years ago

laura spends 4 hours reading a book that is 76 pages long. what is the average number of pages she read per hour?

Mathematics

1 answer:

Studentka2010 [4]2 years ago

5 0

The average number of pages she reads per hour is 19 pages per hour

<h3>How to determine the average number of pages she read per hour?</h3>

The given parameters are:

Number of pages = 76 pages

Number of hours = 4 hours

The average number of pages she reads per hour is calculated using the following formula

Average = Number of pages/Number of hours

Substitute the known values in the above equation

Average = 76 pages/4 hours

Evaluate the quotient

Average = 19 pages per hours

Hence, the average number of pages she reads per hour is 19 pages per hours

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A circle has a radius of 98 units and is centered at (5.9,6.7) write the equation of the circle

Hoochie [10]

In this case, we'll have to carry out several steps to find the solution.

Step 01:

Data

radius = √98

center = (5.9,6.7)

equation of the circle = ?

Step 02:

Equation of the circle

(x - a) ² + (y - b) ² = r ²

(a , b) = center

(x - 5.9) ² + (y - 6.7) ² = (√98) ²

(x - 5.9) ² + (y - 6.7) ² = 98

The answer is:

(x - 5.9) ² + (y - 6.7) ² = 98

6 0

1 year ago

Please help me with the below question.

VMariaS [17]

By letting

$y = \displaystyle \sum_{n=0}^\infty c_n x^{n+r}$

we get derivatives

$y' = \displaystyle \sum_{n=0}^\infty (n+r) c_n x^{n+r-1}$

$y'' = \displaystyle \sum_{n=0}^\infty (n+r) (n+r-1) c_n x^{n+r-2}$

a) Substitute these into the differential equation. After a lot of simplification, the equation reduces to

$5r(r-1) c_0 x^{r-1} + \displaystyle \sum_{n=1}^\infty \bigg( (n+r+1) c_n + (n + r + 1) (5n + 5r + 1) c_{n+1} \bigg) x^{n+r} = 0$

Examine the lowest degree term $\left(x^{r-1}\right)$ , which gives rise to the indicial equation,

$5r (r - 1) + r = 0 \implies 5r^2 - 4r = r (5r - 4) = 0$

with roots at r = 0 and r = 4/5.

b) The recurrence for the coefficients $c_k$ is

$(k+r+1) c_k + (k + r + 1) (5k + 5r + 1) c_{k+1} = 0 \implies c_{k+1} = -\dfrac{c_k}{5k+5r+1}$

so that with r = 4/5, the coefficients are governed by

$c_{k+1} = -\dfrac{c_k}{5k+5} \implies \boxed{g(k) = -\dfrac1{5k+5}}$

c) Starting with $c_0=1$ , we find

$c_1 = -\dfrac{c_0}5 = -\dfrac15$

$c_2 = -\dfrac{c_1}{10} = \dfrac1{50}$

so that the first three terms of the solution are

$\displaystyle \sum_{n=0}^2 c_n x^{n + 4/5} = \boxed{x^{4/5} - \dfrac15 x^{9/5} + \frac1{50} x^{13/5}}$

4 0

2 years ago

Which of the following is equivalent to 3 (small) 4?<br><br> 7<br> 12<br> 64<br> 81

anygoal [31]

Do you mean 3^4?

If you mean this^ the answer would be 81.

4 0

3 years ago

Given y= 1/3x+5, find y when x = -3

Zina [86]

Answer: y = 4

explanation:
y = 1/3(-3) + 5
y = (-3)/3 + 5
y = -1 + 5
y = 4

8 0

2 years ago

I need help simple explanation if possible

Yuki888 [10]

Answer: X=1

Step-by-step explanation:
The hypotenuse is √2 which means that x²+x²=(√2)² using Pythagoras
Simplify and solve
2x²=2
x²=1
X=√1
X=1

8 0

2 years ago