1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
denpristay [2]
2 years ago
11

In the molecular orbital model of cyclobutadiene, how many -antibonding molecular orbitals are there?

Chemistry
1 answer:
Citrus2011 [14]2 years ago
4 0

There are one antibonding molecular orbitals present in molecular orbital model of c.

The cyclobutadiene has a pi system comprised of four  individual atomic p - orbital and thus should have a four pi   molecular orbitals. The compound is the prototypical antiaromatic hydrocarbon with 4 \pi - electrons .  Its rectangular structure is the result of jahn teller reaction which disorder the molecule and lowers its symmetry , converting the triplet to a singlet ground state. It is a small annulene . The  delocalisation energy of the  \pi   electrons of the cyclobutene is predicted to be zero .

To learn more about antibonding molecular orbitals click here

brainly.com/question/14970060

#SPJ4

You might be interested in
How do I study Chemistry efficiently?
TEA [102]
Review and Study Material Before Going to
Class.

Seek Understanding.

Take Good Notes.

Practice Daily.

Take Advantage of Lab Time.

Use Flashcards.

Use Study Groups.

Break Large Tasks Into Smaller Ones.
5 0
2 years ago
Calculate the concentration of formate in a 100mm solution of formic acid at ph 4.15. The pka for formic acid is 3.75
MissTica

The molarity of formic acid is 100 mM or 100\times 10^{-3}M. The dissociation reaction of formic acid is as follows:

HCOOH\leftrightharpoons HCOO^{-}+H^{+}

The expression for dissociation constant of the reaction will be:

K_{a}=\frac{[HCOO^{-}][H^{+}]}{[HCOOH]}

Rearranging,

[HCOO^{-}]=\frac{K_{a}[HCOOH]}{[H^{+}]}

Here, pH of solution is 4.15 thus, concentration of hydrogen ion will be:

[H^{+}]=10^{-pH}=10^{-4.15}=7.08\times 10^{-5}M

Similarly, pK_{a}=3.75 thus,

[K_{a}=10^{-pK_{a}}=10^{-3.75}=1.78\times 10^{-4}M

Putting the values,

[HCOO^{-}]=\frac{(1.78\times 10^{-4}M)(100\times 10^{-3}M)}{(7.08\times 10^{-5}M}=0.2511 M

Therefore, the concentration of formate will be 0.2511 M.

4 0
3 years ago
A molecule contains five atoms and has a molecular weight of 85 g per mole. the atoms are of elements with atomic numbers 1, 6,
inessss [21]

Answer:

            Dichloromethane

Explanation:

As we know the atomic number given belongs to following elements, i.e.

Atomic #                   Element                      M.Mass

   1                           Hydrogen                    1 g.mol⁻¹

   6                          Carbon                        12 g.mol⁻¹

   17                         Chlorine                      35.5 g.mol⁻¹

Also the molecular formula of Dichloromethane is,

                           =  CH₂Cl₂

Putting molar masses of each element,

                          =  (12)₁  +  (1)₂  +  (35.5)₂

                          =  12  +  2  +  71

                          =  85 g.mol⁺¹

Result:

         Hence the only possible structure containing 5 atoms is Dichloromethane.

6 0
3 years ago
How to prepare 1m of a solution​
jenyasd209 [6]

Answer:

To prepare a 1 M solution, slowly add 1 formula weight of compound to a clean 1-L volumetric flask half filled with distilled or deionized water. Allow the compound to dissolve completely, swirling the flask gently if necessary.

Explanation:

have a great day ahead ♥️

5 0
2 years ago
Sodium chloride can be produced by the reaction of sodium metal with chlorine gas. Which is the limiting reactant if 6.70 moles
Alecsey [184]

Answer:

Chlorine gas.

Explanation:

Hello!

In this case, the undergoing chemical reaction is:

2Na+Cl_2\rightarrow 2NaCl

Thus, given the moles of reacting both sodium and chlorine, we compute the moles of sodium chloride yielded by each reactant by considering the 2:2 and 1:2 mole ratios:

n_{NaCl}^{by\ Na}=6.70molNa*\frac{2molNaCl}{2molNa}=6.70molNaCl \\\\n_{NaCl}^{by\ Cl_2}=3.20molCl_2*\frac{2molNaCl}{1molCl_2}=6.40molNaCl

Thus, since chlorine yields less moles of sodium chloride, we infer it is the limiting reactant.

Best regards!

3 0
3 years ago
Other questions:
  • Frank has a paper clip. It has a mass of 9g and a volume of 3cm3. What is its density?
    9·2 answers
  • Is the planet Uranus surface rocky or flat?
    13·1 answer
  • Use the investigation set up below to write a conclusion statement for what is happening to the liquid. Choose the best answer.
    12·1 answer
  • Sodium (Na) and iodine gas (I2) react to form sodium iodine (NaI) .
    11·2 answers
  • At a certain fixed temperature, the reaction A(g) + 2 B(g) → AB2(g) is found to be first order in the concentration of A and zer
    7·1 answer
  • Define chemical change and give an example
    13·2 answers
  • A solution of 6.2 M H2SO4 is diluted from 2.0 L to 3.0 L. What is the molarity of the resulting solution?
    13·1 answer
  • a student observed the shape of the moon once every 7 days during the month of June. which of the following sets of drawings sho
    15·1 answer
  • 6. For each of the following sets of atoms, rank the atoms from smallest to largest atomic radius.
    14·1 answer
  • 1. Differentiate Physical and chemical changes of matter?
    10·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!