Answer:
5.77 L
Solution:
Data Given:
Moles = n = 0.24 mol
Temperature = T = 35 °C + 273 = 308 K
Pressure = P = 1.05 atm
Volume = V = ?
Formula Used:
Let's assume that the hydrogen gas in balloon is acting as an Ideal gas, the according to Ideal Gas Equation,
P V = n R T
where; R = Universal Gas Constant = 0.082057 atm.L.mol⁻¹.K⁻¹
Solving Equation for V,
V = n R T / P
Putting Values,
V = (0.24 mol × 0.082057 atm.L.mol⁻¹.K⁻¹ × 308 K) ÷ 1.05 atm
V = 5.77 L
"S<span>cientists believe that solids are mostly open space" is the statement among the statements given in the question that is true. The correct option among all the options that are given in the question is the second option or option "B". I hope that this answer has actually come to your help.</span>
1) we calculate the molar mass of He (helium) and Kr (Krypton).
atomic mass (He)=4 u
atomic mas (Kr)=83.8 u
Therefore the molar mass will be:
molar mass(He)=4 g/mol
molar mass(Kr)=83.8 g/mol.
1) We can find the next equation:
mass=molar mass x number of moles.
x=number of moles of helium
y=number of moles of helium.
(4 g/mol) x +(83.8 g/mol)y=103.75 g
Therefore, we have the next equation:
(1)
4x+83.8y=103.75
2) We can find other equation:
We have 30% helium atoms and 70% Kryptum atoms, therefore we have 30% Helium moles and 70% of Krypton moles.
1 mol is always 6.022 * 10²³ atoms or molecules, (in this case atoms).
Then:
x=number of moles of helium
y=number of moles of helium.
(x+y)=number of moles of our sample.
x=30% of (x+y)
Therefore, we have this other equation:
(2)
x=0.3(x+y)
With the equations(1) and (2), we have the next system of equations:
4x+83.8y=103.75
x=0.3(x+y) ⇒ x=0.3x+0.3y ⇒ x-0.3x=0.3y ⇒ 0.7 x=0.3y ⇒ x=0.3y/0.7
⇒x=3y/7
We solve this system of equations by substitution method.
x=3y/7
4(3y/7)+83.8y=103.75
lower common multiple)7
12y+586.6y=726.25
598.6y=726.25
y=1.21
x=3y/7=3(1.21)/7=0.52
We have 0.52 moles of helium and 1.21 moles of Krypton.
1 mol=6.022 * 10²³ atoms
Total number of particles=(6.022 *10²³ atoms /1 mol) (number of moles of He+ number of moles of Kr).
Total number of particles=6.022 * 10²³ (0.52+1.21)=6.022 * 10²³ (1.73)=
=1.044 * 10²⁴ atoms.
Answer: The sample have 1.044 * 10²⁴ atoms.
We have that for the Question, it can be said that the mass of Ammonia is
Mass_a=3.162grams
From the question we are told
<em>Ammonia </em>gas has a <u>molar</u> mass of approximately 17 <u>grams </u>per mole. At 290k and 1.2 atm, a sample of <em>ammonia </em>has a volume of 3.7 L. In <em>three </em>to five sentences, explain how you can find the mass of the <em>ammonia</em>. Then, given R= 0.0821L.atm/mol.k, calculate the mass.
Generally the equation for the is mathematically given as
Now the mass of ammonia is
Hence the mass of Ammonia is
Mass_a=3.162grams
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Answer:
ocean basalts
Explanation:
As the sea floor slowly spreads, the igneous rock(ocean basalts) of which it is comprised cools and congeals, recording the earth's current magnetic pole alignment.
