The midsegment is half the length of the base.
1) 32 ÷ 2 = 16
<em>So</em><em>,</em><em> 16 is the midsegment</em>
2) 11 ÷ 2 = 5.5
<em>So, 5.5 is the midsegment</em>
3) 32 ÷ 2 = 16
<em>So</em><em>,</em><em> 16 is the midsegment</em>
<em>4</em><em>)</em><em> </em>14 ÷ 2 = 7
<em>S</em><em>o</em><em>,</em><em> </em><em>7</em><em> </em><em>i</em><em>s</em><em> </em><em>t</em><em>h</em><em>e</em><em> </em><em>m</em><em>i</em><em>d</em><em>s</em><em>e</em><em>g</em><em>m</em><em>e</em><em>n</em><em>t</em>
Answer:
im pretty sure its 10.73, multiply 3.7 and 5.8 then divide 2
IT'S SImple just divid all them toghether 2x2x2x2x2x2x2x2x2=999,0000 and that is ur answer
Answer:

Step-by-step explanation:
We are given that
Radius of end of a log, r= 9 in
Error,
in
We have to find the error in computing the area of the end of the log by using differential.
Area of end of the log, A=


Now,
Approximate error in area

Using the values


Hence, the possible propagated error in computing the area of the end of the log