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LiRa [457]
2 years ago
11

What do I check off ​

Mathematics
2 answers:
Goryan [66]2 years ago
5 0
Answer is A, E and F.

Reason.

364 ____ 225

A = not equal sign
E = greater than or equal to sign
F = greater than sign

Step2247 [10]2 years ago
4 0
A and F are the right answer
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Please help me question 1-4
Galina-37 [17]

The midsegment is half the length of the base.

1) 32 ÷ 2 = 16

<em>So</em><em>,</em><em> 16 is the midsegment</em>

2) 11 ÷ 2 = 5.5

<em>So, 5.5 is the midsegment</em>

3) 32 ÷ 2 = 16

<em>So</em><em>,</em><em> 16 is the midsegment</em>

<em>4</em><em>)</em><em> </em>14 ÷ 2 = 7

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4 0
3 years ago
Least to greatest -1.6,5,2,-7/8,0.9,-6/5
nikdorinn [45]
-1.6,-6/5,-7/8,0,0.9,2,5
8 0
3 years ago
Read 2 more answers
What is the area, in square centimeters, of the shape below? 3.7 cm 5.8 cm​
Fudgin [204]

Answer:

im pretty sure its 10.73, multiply 3.7 and 5.8 then divide 2

3 0
3 years ago
Find the area of the figure
yanalaym [24]

IT'S SImple just divid all them toghether 2x2x2x2x2x2x2x2x2=999,0000 and that is ur answer

8 0
3 years ago
The measurement of the radius of the end of a log is found to be 9 inches, with a possible error of 1/2 inch. Use differentials
enot [183]

Answer:

\pm 9in^2

Step-by-step explanation:

We are given that

Radius of end of a log, r= 9 in

Error, \Delta r=\pm 1/2in

We have to find the error in computing the area of the end of the log by using differential.

Area of end of the log, A=pi r^2

\frac{dA}{dr}=2\pi r

\frac{dA}{dr}=2\pi (9)=18\pi in^2

Now,

Approximate error in area

dA=\frac{dA}{dr}(\Delta r)

Using the values

dA=18\pi (\pm 1/2)

\Delta A\approx dA=\pm 9in^2

Hence, the possible propagated error in computing the area of the end of the log=\pm 9in^2

6 0
3 years ago
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