Answer:
The capacite is C=5.32 uF using the equations of voltage and energy in capacitance
Explanation:
The energy holds is 5 J and the resistor dissipates 2J so the energy total is 3J
Using:

Voltage in this case is the energy dissipated so



Using the equation to find capacitance

F
C= 5.32 uF because u is the symbol for micro that is equal to 
<u>Given that:</u>
Ball dropped from a bridge at the rate of 3 seconds
Determine the height of fall (S) = ?
As we know that, S = ut + 1/2 ×a.t²
u =initial velocity = 0
a= g =9.81 m/s (since free fall)
S = 0+ 1/2 × 9.81 × 3²
<em> S = 44.145 m</em>
<em>44.145 m far is the bridge from water</em>
Answer:
a) the magnitude of r is 184.62
b) the direction is 37.74° south of the negative x-axis
Explanation:
Given the data in the question;
as illustrated in the image blow;
To find the the magnitude of r, we will use the Pythagoras theorem
r² = y² + x²
r = √( y² + x²)
we substitute
r = √((-113)² + (-146)²)
r = √(12769 + 21316 )
r = √(34085 )
r = 184.62
Therefore, the magnitude of r is 184.62
To find its direction, we need to find ∅
from SOH CAH TOA
tan = opposite / adjacent
tan∅ = -113 / -146
tan∅ = 0.77397
∅ = tan⁻¹( 0.77397 )
∅ = 37.74°
Therefore, the direction is 37.74° south of the negative x-axis
The lowest energy of electron in an infinite well is 1.2*10^-33J.
To find the answer, we have to know more about the infinite well.
<h3>What is the lowest energy of electron in an infinite well?</h3>
- It is given that, the infinite well having a width of 0.050 mm.
- We have the expression for energy of electron in an infinite well as,


- Thus, the lowest energy of electron in an infinite well is,

Thus, we can conclude that, the lowest energy of electron in an infinite well is 1.2*10^-33J.
Learn more about the infinite well here:
brainly.com/question/20317353
#SPJ4
The answer should be copper. hope this helps :D