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uysha [10]
3 years ago
7

a cart has 30J or potential energy at the top of a 20m high hill. Assuming no energy is transformed to another form of energy, h

ow much kinetic energy does the cart have when it is halfway down the hill?
Physics
1 answer:
topjm [15]3 years ago
3 0

Answer:

i would say 20J

Explanation:

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A continental tropical air mass is _______ and _______.
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A continental tropical air mass is dry and hot. It is formed over the land and in hot tropical areas. Summer months are when this kind of warm air mass is most noticeable and it can stay for a lengthy period of time.
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4) The mass of Pluto is 1.31 x 1022 kg and its radius is 1.15 x 106 m. What is the acceleration of
Elina [12.6K]

Answer:

0.661 m/s²

Explanation:

g = MG / r²

g = (1.31×10²² kg) (6.67×10⁻¹¹ m³/kg/s²) / (1.15×10⁶ m)²

g = 6.61×10⁻¹ m/s²

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A large rock of mass me materializes stationary at the orbit of Mercury and falls into the sun. Itf the Sun has a mass ms and ra
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Answer:

The answer is v = \sqrt{2G\frac{M_s}{R^2}(R-r_s)}.

Explanation:

From the law of gravity,

F = G \frac{Mm}{r^2}

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the general expression for gravitational potential energy is

U = -G \frac{Mm}{r},

where G is the gravitational constant, M and m are the mass of the attracting bodies, and r is the distance between their centers. The negative sign is because the force approaches zero for large distances, and we choose the zero of gravitational potential energy at an infinite distance away.

However, as the mass of the Sun is much greater than the mass of the rock, the gravitational acceleration is defined as

g = -G \frac{M}{r^2},

(the negative sign indicates that the force is an attractive force), and the potential energy between the rock and the Sun is

U = g M_e R,

which is actually the total energy of the system, because the rock materializes stationary at this point (there is no radial kinetic energy).

When the rock hits the surface of the Sun, almost all potential energy is converted to kinetic energy, but not all because the Sun is not a puntual mass. So the potential energy converted to kinetic energy is

U_p = g M_e(R- r_s),

then, the kinetik energy when the rock hits the surface is

U_k =\frac{1}{2}M_e v^2 = g M_e(R- r_s),

so

v = \sqrt{2g(R-r_s)}

where g is the gravitational acceleration generated by the Sun at R,

g = G \frac{M_s}{R^2}.

8 0
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Explanation:

In a heat exchange, the temperature change is inversely proportional to the specific heat capacity. Since substance A has a heat capacity that is much greater than that of substance B, the temperature change of substance A will be less than the temperature change of substance B. Therefore, the final temperature is closer to that of 30^\circ C than 80^\circ C.

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How do we get heat on Earth? Does thermal energy travel directly from the sun?
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