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Semenov [28]
3 years ago
15

A car heading north collides at an intersection with a truck heading east. if they lock together and travel 28 m.s at 46 degrees

north of east just after the collision, how fast was the car initially traveling? assume that the two vehicles have the same mass.
A) 30 m/s
B) 80 m/s
C) 20 m/s
D) 40 m/s
Physics
1 answer:
Dominik [7]3 years ago
4 0

Answer:

C) 20 m/s

Explanation:

The collision of the car and truck will give a single resultant velocity due to equal masses.

We'll treat this question as a vector question.

The velocity profile will form a right angle triangle.

To calculate the velocity of the car

Let the velocity be x

Sina = x/28

Sin46= x/28

0.7193*28 = x

20 = x

X = 20 m/s

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This is defined as the rate of change of velocity which time. It is expressed as

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<h3>How to determine the final velocity</h3>

The following data were obtained from the question

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The final velocity can be obtained as follow:

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Answer:

Explanation:

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