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Alex_Xolod [135]
2 years ago
6

Please answer my question correctly​

Mathematics
1 answer:
morpeh [17]2 years ago
4 0

Answer:

Step-by-step explanation:

Firstly, we know the formula for percentage which is  P = B x R

where Percentage is associated with of,

        Base  is associated with %  and

       Rate is associated with is

1.  We have, 30% × N=  12

=   <u>30</u>  x   N      =   12

   100  

Multiplying both sides by 100 and dividing both sides by 30,

we have  N = 12 ×  <u>100</u>        N  =  12  x   3.33    

                               30

N  = 40.

P = 12,   B = N and R = 30

2.  N is 30%  of 12000  =  30/100 x 12000   =  3600

P = N,   R = 30 ,  B = 12000

3.  26 is 40% of N.      =  26 X 100 / 40  =  65

P = 26 ,  R = 40,  B = N

4.  60 IS N% OF 80  =   N/100  x 80  = 60

                                       <u>80n</u>   = <u>60</u>  

                                      100        1

cross multiply.   80n  = 6000   N = 75

P = 60,  R = N  ,  B = 80

5. 75% of N is 30  

N = 75 X100 / 30   =  75 X 3.33  N = 250

P= 30,  R = 75,  B = 30

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Step-by-step explanation:

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Miquel created the table below to show how he uses the money he earns at work
lara [203]

<u>Complete Question with table is attached</u>

<u>Answer:</u>

Miguel will save money of $90 if he earns $120.00

<u>Step-by-step explanation:</u>

The figure attached clearly shows the ratio of his earnings and savings. We have to find what would be the savings amount if he earn $120.00. So, first we have to calculate the percentage of ratio of his earnings and savings. As per the data given in the figure,

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Likewise, calculate for all given data. If he earns $50.00 then he saves $37.50

           \frac{\$ 37.50}{\$ 50.00} \times 100=0.75 \times 100=75 \%

If he earns  $150.00 and save $112.50,

           \frac{\$ 112.50}{\$ 150.00} \times 100=0.75 \times 100=75 \%

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6 0
3 years ago
Read 2 more answers
Quadratic equations and complex numbers PLEASE HELPPPP ASAP
kondor19780726 [428]

we are given

27x^3-1=0

we can also write it as

(3x)^3-(1)^3=0

now, we can use factor formula

a^3-b^3=(a-b)(a^2+ab+b^2)

we can use above formula

we get  

(3x)^3-(1)^3=(3x-1)((3x)^2+3x\times 1+(1)^2)

now, we can simplify it

27x^3-1=(3x-1)(9x^2+3x+1)

now, we can set it to 0

27x^3-1=(3x-1)(9x^2+3x+1)=0

and then we can solve for x

(3x-1)(9x^2+3x+1)=0

3x-1=0

x=\frac{1}{3}

9x^2+3x+1=0

now, we can use quadratic formula

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now, we can plug values

and we get

x=\frac{-3\pm \sqrt{3^2-4\cdot \:9\cdot \:1}}{2\cdot \:9}

x=-\frac{1}{6}+i\frac{\sqrt{3}}{6},\:x=-\frac{1}{6}-i\frac{\sqrt{3}}{6}

So, we will get solution as

x=\frac{1}{3},\:x=-\frac{1}{6}+i\frac{\sqrt{3}}{6},\:x=-\frac{1}{6}-i\frac{\sqrt{3}}{6}...............Answer

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