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Alex_Xolod [135]
2 years ago
6

Please answer my question correctly​

Mathematics
1 answer:
morpeh [17]2 years ago
4 0

Answer:

Step-by-step explanation:

Firstly, we know the formula for percentage which is  P = B x R

where Percentage is associated with of,

        Base  is associated with %  and

       Rate is associated with is

1.  We have, 30% × N=  12

=   <u>30</u>  x   N      =   12

   100  

Multiplying both sides by 100 and dividing both sides by 30,

we have  N = 12 ×  <u>100</u>        N  =  12  x   3.33    

                               30

N  = 40.

P = 12,   B = N and R = 30

2.  N is 30%  of 12000  =  30/100 x 12000   =  3600

P = N,   R = 30 ,  B = 12000

3.  26 is 40% of N.      =  26 X 100 / 40  =  65

P = 26 ,  R = 40,  B = N

4.  60 IS N% OF 80  =   N/100  x 80  = 60

                                       <u>80n</u>   = <u>60</u>  

                                      100        1

cross multiply.   80n  = 6000   N = 75

P = 60,  R = N  ,  B = 80

5. 75% of N is 30  

N = 75 X100 / 30   =  75 X 3.33  N = 250

P= 30,  R = 75,  B = 30

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A product is made up of components A, B, C, D, E, F, G, H, I, and J. Components A, B, C, and F have a 1/10,000 chance of failure
Svetach [21]

Answer:

The overall reliability is 99.7402 %

Step-by-step explanation:

The overall reliability of the product is calculated as the product of the working probability of the components.

For components A,B,C and F we have :

P(failure)=\frac{1}{10000}

⇒

P(Work)=1-\frac{1}{10000}=\frac{9999}{10000}=0.9999

For components D,E,G and H we have :

P(failure)=\frac{3}{10000}

⇒

P(Work)=1-\frac{3}{10000}=\frac{9997}{10000}=0.9997

Finally, for components I and J :

P(failure)=\frac{5}{10000}

⇒

P(Work)=1-\frac{5}{10000}=\frac{9995}{10000}=0.9995

Now we multiply all the working probabilities. We mustn't forget that we have got ten components in this case :

Components A,B,C and F with a working probability of 0.9999

Components D,E,G and H with a working probability of 0.9997

Components I and J with a working probability of 0.9995

Overall reliability = (0.9999)^{4}(0.9997)^{4}(0.9995)^{2}=0.997402

0.997402 = 99.7402 %

6 0
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Marta_Voda [28]
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I’d really appreciate help with these...
Irina-Kira [14]

Answer:

+- 5 and +- 3

Step-by-step explanation:

qn 2:

4r² = 91 + 9

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r² = 9

r = +- 3

7 0
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<span>sin(36)(9) = 5.29
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