Answer:By turning the electrical current off
Explanation:Trust me I took the test
The temperature of the air above it
Answer:
Magnitude of force on wheel B is 4 N
Explanation:
Given that
![I=mr^2](https://tex.z-dn.net/?f=I%3Dmr%5E2)
For wheel A
m= 1 kg
d= 1 m,r= 0.5 m
F=1 N
We know that
T= F x r
T=1 x 0.5 N.m
T= 0.5 N.m
T= I α
Where I is the moment of inertia and α is the angular acceleration
![I_A=1 \times 0.5^2\ kg.m^2](https://tex.z-dn.net/?f=I_A%3D1%20%5Ctimes%200.5%5E2%5C%20kg.m%5E2)
![I_A=0.25\ kg.m^2](https://tex.z-dn.net/?f=I_A%3D0.25%5C%20kg.m%5E2)
T= I α
0.5= 0.25 α
![\alpha = 2\ rad/s^2](https://tex.z-dn.net/?f=%5Calpha%20%3D%202%5C%20rad%2Fs%5E2)
For Wheel B
m= 1 kg
d= 2 m,r=1 m
![I_B=1 \times 1^2\ kg.m^2](https://tex.z-dn.net/?f=I_B%3D1%20%5Ctimes%201%5E2%5C%20kg.m%5E2)
![I_B=1 \ kg.m^2](https://tex.z-dn.net/?f=I_B%3D1%20%5C%20kg.m%5E2)
Given that angular acceleration is same for both the wheel
![\alpha = 2\ rad/s^2](https://tex.z-dn.net/?f=%5Calpha%20%3D%202%5C%20rad%2Fs%5E2)
T= I α
T= 1 x 2
T= 2 N.m
Lets force on wheel is F then
T = F x r
2 = F x 1
So F= 2 N
Magnitude of force on wheel B is 2 N