Part A)
First of all, let's convert the radii of the inner and the outer sphere:


The capacitance of a spherical capacitor which consist of two shells with radius rA and rB is


Then, from the usual relationship between capacitance and voltage, we can find the charge Q on each sphere of the capacitor:

Now, we can find the electric field at any point r located between the two spheres, by using Gauss theorem:

from which

In part A of the problem, we want to find the electric field at r=11.1 cm=0.111 m. Substituting this number into the previous formula, we get

And so, the energy density at r=0.111 m is

Part B) The solution of this part is the same as part A), since we already know the charge of the capacitor:

. We just need to calculate the electric field E at a different value of r: r=16.4 cm=0.164 m, so

And therefore, the energy density at this distance from the center is
Answer:
Explanation:
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Answer:
The time it will take for the car to reach a velocity of 28 m/s is 7 seconds
Explanation:
The parameters of the car are;
The acceleration of the car, a = 4 m/s²
The final velocity of the car, v = 28 m/s
The initial velocity of the car, u = 0 m/s (The car starts from rest)
The kinematic equation that can be used for finding (the time) how long it will take for the car to reach a velocity of 28 m/s is given as follows;
v = u + a·t
Where;
v = The final velocity of the car, v = 28 m/s
u = The initial velocity of the car = 0 m/s
a = The acceleration of the car = 4 m/s²
t = =The time it will take for the car to reach a velocity of 28 m/s
Therefore, we get;
t = (v - u)/a
t = (28 m/s - 0 m/s)/(4 m/s²) = 7 s
The time it will take for the car to reach a velocity of 28 m/s, t = 7 seconds.
The answer is A because at a young age children will not understand and they need to learn at the appropriate level
It would <span>keep rolling without slowing down if no friction acted upon it.
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