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yan [13]
2 years ago
12

What is (-7624928) * 997 + 7624928 * (-3)

Mathematics
2 answers:
DiKsa [7]2 years ago
5 0

Answer:

<u><em>-7624928000 </em></u><em>is the right answer.</em>

Step-by-step explanation:

<em> (-7624928) × 997 + 7624928 × (-3)</em>

<em>= -7602053216 + (-22874784)</em>

= <u><em>-7624928000</em></u><em>        </em><u><em>Ans..</em></u>

Hope its helpful :-)

If so, please mark me as brainlist :-)

xxTIMURxx [149]2 years ago
5 0

Answer:

Step-by-step explanation:

=(-7624928) * 997 + 7624928 * (-3)

=-7602053216+(-22874784)

=-7624928000

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Answer:

critical value = 1.645

The 90% confidence interval = ( -22.62, -17.58)

Step-by-step explanation:

Given that:

the sample  size n_1 = 178

the sample size n_2 = 226

the sample mean \overline x_1 = 54.4

the sample mean \overline x_2 = 74.5

population standard deviation \sigma_1 = 18.58

population standard deviation \sigma_2 = 9.52

level of significance ∝ = 1 - 0.90 = 0.10

The critical value for Z_{\alpha/2} = Z _{0.10/2} = Z_{0.005} is 1.645

For the construction of our confidence interval, we use 90% since that is used to find the critical value.

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The margin of error = Z \times\sqrt{\dfrac{\sigma_1^2}{n_1} + \dfrac{\sigma_2^2}{n_2}}

1.645 \times\sqrt{\dfrac{18.58^2}{178} + \dfrac{9.52^2}{226}}

1.645 \times\sqrt{\dfrac{345.2164}{178} + \dfrac{90.6304}{226}}

1.645 \times\sqrt{2.34042}

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The lower limit = ( \overline x_1 - \overline x_2) - (M.O.E)

= ( 54.4-74.5) - (2.52)

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The upper limit = ( \overline x_1 - \overline x_2) + (M.O.E)

= ( 54.4-74.5) + (2.52)

= -20.1 + 2.52

= -17.58

The 90% confidence interval = ( -22.62, -17.58)

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