Question

James and Reggie both collect old coins. Together, they have a total of 60 coins. If James would agree to give 1/4 of his coins to Reggie, they would then have exactly the same number of coins. How many more cons does James have (compared to the number of coins Reggie has)?

Answer 1

Answer:

James has 20 more coins than Reggie

Step-by-step explanation:

Given:

Total number of coins with James and Reggie = 60

If James would agree to give 1/4 of his coins to Reggie, they would then have exactly the same number of coins

To find: number of coins with James and Reggie

Solution:

Let x denote number of coins with James and y denote number of coins with Reggie.

According to question,

$x+y=60\\x-\frac{x}{4} =y+\frac{x}{4} \\x-y=\frac{2x}{4} \\x=2y$

Put $x=2y$ in $x+y=60$

$2y+y=60\\3y=60\\y=\frac{60}{3}=20\\ x=2y=2(20)=40$

So,

number of coins with James = 40

number of coins with Reggie = 20

James has 20 more coins than Reggie