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taurus [48]
3 years ago
6

A sample of a substance burns more rapidly in pure oxygen than in air. which factor is most responsible for this high rate of re

action?
Physics
1 answer:
zmey [24]3 years ago
3 0
I had to look for the options and here is my answer. Based on the given substance above that burns faster in pure oxygen than in air, the factor that is most responsible for this kind of reaction is the concentration of the reactants. This answer is based on the actual options attached to this question.
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In this system, the equilibrium lies to the<br> and the reaction favors the
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Answer: reactants to this system,...

Explanation:

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The majority of the sun's energy that reaches Earth is __________. View Available Hint(s) The majority of the sun's energy that
Lera25 [3.4K]

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not captured for use by living things

Explanation:

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3 years ago
A food department is kept at â12°c by a refrigerator in an environment at 30°c. the total heat gain to the food department is
slava [35]

As per energy conservation in the reversible engine we can say

Q_2 + W = Q_1

here we know that

Q_2 = 3300 kJ/h

Q_1 = 4800 kJ/h

now from above equation

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W = 1500 kJ/h

now we can convert it into kW

W = 1500\times \frac{kJ}{3600s}

W = 0.42 kW

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now to find COP we know that

COP = \frac{Q_2}{W}

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3 0
3 years ago
Can someone answer and explain these questions?
Andru [333]

Answer:

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Explanation:

7 0
2 years ago
The a992 steel rod bc has a diameter of 50 mm and is used as a strut to support the beam. determine the maximum intensity w of t
EastWind [94]

Answer:

w = 11.211 KN/m

Explanation:

Given:

diameter, d = 50 mm

F.S = 2

L = 3

Due to symmetry, we have:

Ay = By = \frac{w * 6}{2} = 3w

P_c_r = 3w * F.S = 3w * 2.0 = 6w

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To find the maximum intensity, w, let's take the Pcr formula, we have:

P_c_r = \frac{\pi^2 E I}{(KL)^2}

Let's take k = 1

E = 200*10^9

Substituting figures, we have:

6w = \frac{\pi^2 * 200*10^9 * 3.067*10^-^7}{(1 * 3)^2}

Solving for w, we have:

w = \frac{67266.84}{6}

w = 11211.14 N/m = 11.211 KN/m

Since Area, A= pi * (0.05)²

\sigma _c_r = \frac{w}{A}

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The maximum intensity w = 11.211KN/m

3 0
3 years ago
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