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Fittoniya [83]
3 years ago
10

A garden hose with an inside diameter of 0.75 inches is used to fill a round swimming pool 3.0 m in diameter. How many hours wil

l it take to fill the pool to a depth of 1.0 m if water flows from the hose at a speed of 0.30 m/s? Enter your answer without units.
Physics
1 answer:
bagirrra123 [75]3 years ago
3 0

Answer:

23

Explanation:

First, we need to convert the hose diameter from inches to meters.

0.75 in × (2.54 cm / in) × (1 m / 100 cm) = 0.0191 m

Calculate the flow rate given the velocity and hose diameter:

Q = vA

Q = v (¼ π d²)

Q = (0.30 m/s) (¼ π (0.0191 m)²)

Q = 8.55×10⁻⁵ m³/s

Find the volume of the pool:

V = π r² h

V = π (1.5 m)² (1.0 m)

V = 7.07 m³

Find the time:

t = V / Q

t = (7.07 m³) / (8.55×10⁻⁵ m³/s)

t = 82700 s

t = 23 hr

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These are two questions and two answers.

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Answer: 2

Explanation:

1) Formula: momentum = mass * velocity

2) momentum C = mass C * velocity C

3) momentum D = mass D * velocity D.

4) C and D have the same momentum =>

mass C * velocity C = mass D * velocity D

5) mass C = (1/2) mass D => mass C / mass C = 1/2

6) use in the equation stated in the point 4)

velocit C / velocity D = mass D / mass C

using the equation stated in point 5:

mass D / mass C = 1 / [ mass C / mass D] = 1 / [1/2] = 2

=>

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Part 2: <span>ratio of kinetic energy C to kinetic energy D.
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Answer: 2

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If the average pitcher is releasing the ball from a height of 1.8 m above the ground, and the pitcher's mound is 0.2 m higher th
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The distance between the pitcher's mound and the catcher's box is about 60'6", which translates to 18.44 m. An average pitcher can pitch with speeds ranging from 88 mph to 97 mph, which is from 39.3 m/s to 43.4 m/s.

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The horizontal motion of the ball is uniform motion since no force acts on the ball ( assuming no air resistance) and hence the acceleration of the ball along the horizontal direction is zero.

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x=ut

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