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2 years ago

6

What mass of water is required to absorb 4.7 x 10 to the 5th power J of energy from a car engine while the temperature increases

from 298K to 355 K
HELPPPPP

1 answer:

crimeas [40]2 years ago

3 0

I would answer but the other guy got here first and I don’t know the answer sorry

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Name the principle in which rocket work.

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The rocket engine works on the basic principle proposed by Newton which is Newton’s Third Law.

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2 years ago

A dog has a mass of 60kg and an acceleration of 2m/s/s. What is the force of the dog?

attashe74 [19]

Answer:

120 N

Explanation:

F=ma therefore 60kg times 2m/s^2 is 120 N

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2 years ago

Topic Gravitational force amd firld strength.. help me please

I am Lyosha [343]

The gravitational force between <em>m₁</em> and <em>m₂</em> has magnitude

$F_{1,2} = \dfrac{Gm_1m_2}{x^2}$

while the gravitational force between <em>m₁</em> and <em>m₃</em> has magnitude

$F_{1,3} = \dfrac{Gm_1m_3}{(15-x)^2}$

where <em>x</em> is measured in m.

The mass <em>m₁</em> is attracted to <em>m₂</em> in one direction, and attracted to <em>m₃</em> in the opposite direction such that <em>m₁</em> in equilibrium. So by Newton's second law, we have

$F_{1,2} - F_{1,3} = 0$

Solve for <em>x</em> :

$\dfrac{Gm_1m_2}{x^2} = \dfrac{Gm_1m_3}{(15-x)^2} \\\\ \dfrac{m_2}{x^2} = \dfrac{m_3}{(15-x)^2} \\\\ \dfrac{(15-x)^2}{x^2} = \dfrac{m_3}{m_2} = \dfrac{60\,\rm kg}{40\,\rm kg} = \dfrac32 \\\\ \left(\dfrac{15-x}x\right)^2 = \dfrac32 \\\\ \left(\dfrac{15}x-1\right)^2 = \dfrac32 \\\\ \dfrac{15}x - 1 = \pm \sqrt{\dfrac32} \\\\ \dfrac{15}x = 1 \pm \sqrt{\dfrac32} \\\\ x = \dfrac{15}{1\pm\sqrt{\dfrac32}}$

The solution with the negative square root is negative, so we throw it out. The other is the one we want,

$x \approx 6.74\,\mathrm m$

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2 years ago

Will two separate 50db sounds together constitute a 100db sound explain mathematical

vfiekz [6]

Putting together two distinct 50 dB sound, do not create a 100 dB sound. Since decibels are logarithm of energy, creating two sounds together only makes the energy increase but the logarithm only goes up by somehow little. So increasing the sound by 10 dB, only makes it 10000 times louder because each 10 dB increase in sound makes the sound 10 times louder.

Twice as loud is an increase of 10Log (2) = 3.01 dB. So, 53,01 dB is twice as loud as 50dB.

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3 years ago

A boat moves through the water with two forces acting on it. One is a 2.51×103 N forward push by the motor, and the other is a 1

telo118 [61]

Answer:

Acceleration $a=0.455m/sec^2$

Explanation:

We have given that the force by the motor $F=2.51\times 10^3N=2510N$

Resistive force by the water $F=1.88\times 10^3N=1880N$

So net force $F_{NET}=2510-1880=630N$

Mass of the boat = 1384.1 kg

According to newton's second law F=Ma, here M is mass and a is acceleration

So $630=1384.1\times a$

$a=0.455m/sec^2$

7 0

2 years ago