Determine the acid dissociation constant (Ka) for a 0.200 M solution of hydrogen sulfate ion with
1 answer:
The acid dissociation constant(Ka) is 0.0095
The reaction for this dissociation of acid is
HSO4 ⇄H+ + SO4 -2
The dissociation constant can be determined from the following expression
[H+] = 10-PH
= 10-1.35
[H+] = 0.0447
[H+] = 0.0447 mol / L
From equation, [H+] = [SO4-2] = 0.0447 mol / L
[SO4-2] = 0.0447 mol / L
From the values of [H+], [SO4-2] and [HSO4] Ka can be calculated as follows,
Ka = 0.0447 * 0.0447 / 0.200
= 0.0019 / 0.200
= 0.0095
Hence the value of the acid dissociation constant (Ka) for the given reaction is 0.0095
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When one -NH₂ group is replaced by -COOH group the cystine is converted into an acidic compound with three COOH groups and a NH₂ group. Also, one asymmetric carbon will convert into a symmetrical carbon with a loss of one chiral carbon.
In second step, when another NH₂ is replaced by COOH, the acidic strength of resulting compound will increase along with conversion of last chiral carbon into symmetric carbon.
Therefore, the final structure will be acidic in nature with zero chiral carbons as shown in figure attached below.
