Consider a system of nitrogen with temperature of 288k and pressure of 8 mpa what is the compressibility factor?
1 answer:
The compressibility factor is 1.1.
Temperature of Nitrogen = 288 K
Pressure of Nitrogen = 8mpa
The ideal gas law's departure is compensated for by the compressibility factor (Z). An equation of state or industry correlation based on the following relationship is used to compute the compressibility factor:
PV = ZRT
Z ~f (composition, P, T)
where,
Z = compressibility factor at P, T for a given composition.
P = absolute pressure.
T = temperature.
R = universal gas constant.
V =
= (Z × 8.314 × 288) / 8 × 10⁷
= (299.30 × 10⁻⁷) Z m³/kg
The reduced temperature is the ratio of the temperature of the gas to its critical temperature. Similarly, the reduced pressure is the ratio of the gas pressure to its critical pressure as described in the following equations:
P – Absolute pressure of gas
T – Absolute temperature of gas
Tr – Reduced temperature
Pr – Reduced pressure
Tc – Critical temperature
Pc – Critical pressure
Z = 1.1 (from the compressibility chart)
V = 329.23 10⁻⁷ m³/kg
Therefore, the compressibility factor is 1.1.
Learn more about compressibility factor here:
#SPJ4
You might be interested in
Answer: Option (c) is the correct answer.
Explanation:
A limiting reagent is defined as a reagent that completely gets consumed in a chemical reaction. A limiting reagent limits the formation of products.
For example, we have given 5 mol of A and the reaction is
Whereas when 4 mol B will react with 2 mol of A. Hence, 8 mol of B will react with 4 mol A as follows.
= 4 mol
As, the given moles of A is more than the required moles. Thus, it is considered as an excess reagent.
Hence, B is a limiting reagent because it limits the formation of products.
Thus, we can conclude that limiting reactant is the term used to describe the reactant that is used up completely and controls the amount of product that can be produced during a chemical reaction.