Answer:
Hello your question is poorly written below is the complete question
Suppose the battery in a clock wears out after moving Ten thousand coulombs of charge through the clock at a rate of 0.5 Ma how long did the clock run on does battery and how many electrons per second slowed?
answer :
a) 231.48 days
b) n = 3.125 * 10^15
Explanation:
Battery moved 10,000 coulombs
current rate = 0.5 mA
<u>A) Determine how long the clock run on the battery. use the relation below</u>
q = i * t ----- ( 1 )
q = charge , i = current , t = time
10000 = 0.5 * 10^-3 * t
hence t = 2 * 10^7 secs
hence the time = 231.48 days
<u>B) Determine how many electrons per second flowed </u>
q = n*e ------ ( 2 )
n = number of electrons
e = 1.6 * 10^-19
q = 0.5 * 10^-3 coulomb ( charge flowing per electron )
back to equation 2
n ( number of electrons ) = q / e = ( 0.5 * 10^-3 ) / ( 1.6 * 10^-19 )
hence : n = 3.125 * 10^15
Answer:
1. It won't break
2. 0.5 squared meters
Explanation:
1. Pressure (P) is force (F) exerted over an area(A). Greater the force or smaller the area, the pressure will be greater. This is presented by an equation:
P = F / A
This metallic object can be placed on the table in 3 different positions, depending on which its side is pressed against the table. Since its dimensions are 3 • 6 • 8 m, surface areas of these sides are:
A1 = 3 • 6 = 18m^2
A2 = 3 • 8 = 24m^2
A3 = 6 • 8 = 48m^2
It is already stated that the smaller are, greater the pressure, so this object will exert the greatest pressure if it's placed on the table with its 18m^2 side. In this case, pressure will be:
P = 400N / 18m^2
P = 22.2 N/m^2 (N/m^2 is the same unit as Pascal)
So, the table can withstand 250 Pa of pressure, the object exerts only 22.2 Pa, which means that the glass table won't break.
2. Again, we need to know the equation that connects the force and the pressure, and that is:
P = F / A
In this case, we have both the force and the pressure, and we want to find the surface of the area. From the previous equation, area can be found as:
A = F / P
A = 20N / 40Pa (N/m^2)
A = 0.5 m^2
So, the answer is: this pressure is exerted on the area of half of squared metar.
Answer:
no way to tell since the ocean surface is moving too violently it's not possible to determine the reflected angle
Answer:
3.39
Explanation:
Given that
Volume, v = 3.92*10^3 cm³ we convert the volume from cm³ to m³ and we have 0.00392
Pressure, P = 1.25*10^5 Pa
Average Kinetic Energy, K.E = 3.6*10^-22 J
We use the gas law formula,
PV = nRT
Making n subject of the formula, we have
n = PV/RT
Solving for n, we have
n = (1.25*10^5 Pa * 0.00392 m³) / 8.314 * T
n = 4.9*10^8 / 8.314 * T
n = 490 / 8.314T
n = 58.94/T
Note that average kinetic energy is given as
K.E(avg) = 3/2K.T,
3/2 K.T = 3.6*10^-22 J
where K = 1.38*10^-23
T = (3.6*10^-22 J * 2) / (3 * 1.38*10^-23)
T = 17.39
Substitute for T, we have
n = 58.94 / 17.39
n = 3.39
Answer:
1) maximum electric field strength = 0.016 V/m
2)maximum magnetic field strength = 5.33 x 10^(-11) T
3) wavelength = 3 x 10^(8)m
Explanation:
A) We are given;
Frequency (f) = 1 Hz
Maximum Potential ΔV = 4 mV = 4 x 10^(-3) V
Length; d = 0.25 m
Now, maximum potential formula is given as;
ΔV = E_o•d
Where E_o is maximum electric field strength.
Thus,
E_o= ΔV/d = (4 x 10^(-3))/0.25 = 0.016 V/m
B) The maximum magnetic field strength is given by;
B_o = E_o/c
Where;
c is speed of light = 3 x 10^(8)
B_o is maximum magnetic field strength
Thus,
B_o = 0.016/(3 x 10^(8)) = 5.33 x 10^(-11) T
C) Speed of any electromagnetic wave is given by;
c = fλ
Where;
f is frequency
λ is wavelength
c is speed of light = 3 x 10^(8)
Thus, making λ the subject,
λ = c/f
λ = (3 x 10^(8))/1 = 3 x 10^(8)m