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In-s [12.5K]
2 years ago
12

The position of a particle is given by the function x=(5t3−8t2+12)m, where t is in s. at what time does the particle reach its m

inimum velocity?

Physics
2 answers:
Lady_Fox [76]2 years ago
8 0

The particle reach its minimum velocity at time 1.06 sec.

The function is given as

x=5t^3-8t^2+12

Differentiating the above equation with respect to time, to obtain the velocity

dx/dt=v=15t^2-16t

For maximum and minimum values, put dx/dt=0

15t^2-16t=0

On solving the equation, t=0, 1.06

Therefore at time t=1.06 sec, the particle has the minimum value of velocity.


Stella [2.4K]2 years ago
8 0

The particle reaches its minimum velocity at t = 0 s or t = 16/15 s

<h3>Further explanation</h3>

Acceleration is rate of change of velocity.

\large {\boxed {a = \frac{v - u}{t} } }

\large {\boxed {d = \frac{v + u}{2}~t } }

<em>a = acceleration ( m/s² )</em>

<em>v = final velocity ( m/s )</em>

<em>u = initial velocity ( m/s )</em>

<em>t = time taken ( s )</em>

<em>d = distance ( m )</em>

Let us now tackle the problem!

<u>Given:</u>

x = ( 5t^3 - 8t^2 + 12) ~ m

To find the velocity function, we will derive the position function above.

v = \frac{dx}{dt}

v = 5(3)t^{3-1} - 8(2)t^{2-1}

v = ( 15t^2 - 16t ) ~ m/s

Next to calculate the time to reach its minimum speed, then v = 0 m/s

0 = ( 15t^2 - 16t )

0 = t( 15t - 16)

\large {\boxed {t = 0 ~s ~ or ~ t = 16/15 ~ s} }

<h3>Learn more</h3>
  • Velocity of Runner : brainly.com/question/3813437
  • Kinetic Energy : brainly.com/question/692781
  • Acceleration : brainly.com/question/2283922
  • The Speed of Car : brainly.com/question/568302

<h3>Answer details</h3>

Grade: High School

Subject: Physics

Chapter: Kinematics

Keywords: Velocity , Driver , Car , Deceleration , Acceleration , Obstacle

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Explanation:

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in a one dimensional collision, a 4kg object with 5ms^1 and 6 kg object with 2ms^1 have initial velocity, the magnitude of impulse is 12 , 18

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lisov135 [29]
If the car travels
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Answer:

A

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