Question

At table tennis ball has a positive charge of 4.50 × 10-8 coulombs. It experiences a force of 2.72 × 10-3 newtons due to an electric field. What is the strength of the electric field?
2.72 × 10-10 newtons/coulomb

4.50 × 10-11 newtons/coulomb

6.04 × 104 newtons/coulomb

1.24 × 105 newtons/coulomb

Answer 1

Answer:

Strength of electric field,  E = 6.04 × 10⁴ newtons/coulomb

Explanation:

It is given that,

Charge on tennis ball, $q=4.5\times 10^{-8}\ C$

It experiences a force of $F=2.72\times 10^{-3}\ N$

The electric force is given by the product of electric charge and magnitude of electric field.

i.e.

F = q × E

So, $E=\dfrac{F}{q}$

$E=\dfrac{2.72\times 10^{-3}}{4.5\times 10^{-8}}$

E = 60444.5 N/C

or

$E=6.04\times 10^4\ N/C$

The strength of the electric field is $6.04\times 10^4\ N/C$.Hence, the correct option is (C) " 6.04 × 10⁴ newtons/coulomb "

Answer 2

The answer is 6.04 × 10^4 N/C.
Formula for the strength of the electric field is:
E = F/q
E = 2.72 × 10^-3 N/4.50 × 10^-8 C
E = 0.60444 × 10^5 N/C
E = 6.04 × 10^4 N/C