Answer:
False
Step-by-step explanation:
A composite figure would be any irregular shapes and can be made up of multiple shapes
These matrices ARE inverses of each other!
The answer is 705.6 cm^3.
Remember that volume of a box, rectangular prism, is: V = LWH.
So, V = 7(9)(11.2) = 705.6 cm^3
Step-by-step explanation:
Solve for xsin3⁡x+cos3⁡x=1" role="presentation" style="margin: 0px; padding: 0px; border: 0px; font-style: normal; font-variant: inherit; font-weight: normal; font-stretch: inherit; line-height: normal; font-family: inherit; font-size: 15px; vertical-align: baseline; box-sizing: inherit; display: inline; text-indent: 0px; text-align: left; text-transform: none; letter-spacing: normal; word-spacing: normal; overflow-wrap: normal; white-space: nowrap; float: none; direction: ltr; max-width: none; max-height: none; min-width: 0px; min-height: 0px; position: relative;">xsin3x+cos3x=1xsin3x+cos3x=1
sin3⁡x+cos3⁡x=1(sin⁡x+cos⁡x)(sin2⁡x−sin⁡x⋅cos⁡x+cos2⁡x)=1(sin⁡x+cos⁡x)(1−sin⁡x⋅cos⁡x)=1" role="presentation" style="margin: 0px; padding: 0px; border: 0px; font-style: normal; font-variant: inherit; font-weight: normal; font-stretch: inherit; line-height: normal; font-family: inherit; font-size: 15px; vertical-align: baseline; box-sizing: inherit; display: inline; text-indent: 0px; text-align: left; text-transform: none; letter-spacing: normal; word-spacing: normal; overflow-wrap: normal; white-space: nowrap; float: none; direction: ltr; max-width: none; max-height: none; min-width: 0px; min-height: 0px; position: relative;">sin3x+cos3x=1(sinx+cosx)(sin2x−sinx⋅cosx+cos2x)=1(sinx+cosx)(1−sinx⋅cosx)=1
Answer: A= 460 mm2
Step-by-step explanation:
Hi, since the circumference formula is :
C = 2 π r
Where r is the radius, we can solve the formula for the radius replacing with the value given:
76 =2 π r
76 / (2 π) = r
r = 12.1 mm
Now , we have to apply the formula for the area of a circle.
A = π r^2
A = π (12.1)^2
A= 459.96 mm2= 460 mm2 (rounded to the nearest tenth, since .9 is higher than .5)
Feel free to ask for more if needed or if you did not understand something.
