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cluponka [151]
2 years ago
14

Geometry: Write a formal proof, ASAP!!!

Mathematics
1 answer:
yulyashka [42]2 years ago
7 0

{\qquad\qquad\huge\underline{{\sf Answer}}}

Here we go ~

As we can see in the figure, lines m and n are parallel to each other. so we can apply Angle pair properties ~

So,

\qquad \sf  \dashrightarrow \:  \angle1  \cong \angle2

[ they form corresponding angle pair ]

and it's given that :

\qquad \sf  \dashrightarrow \:  \angle2 \cong\angle 3

therefore, by using above information. we can conclude that :

\qquad \sf  \dashrightarrow \:  \angle1 \cong \angle3

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AB = 8x + 3, BC =2x + 7 and AC = 80 Find value of AB and BC
yulyashka [42]

Answers:
 1)  The value of <em>AB</em>  is:  " 59 units."
 2) The value of <em>BC</em>  is: "21 units."
_______
 3) The value of <em>AB</em>  +  <em>BC</em> ;

     =   59  units  +   21  units ;

     =   [the value of <em>AC </em>] ;

     =  {" 80 units ".}.
_______

<u>Step-by-step explanation:  </u>                                          

Given the following—and based on the assumption that we are dealing with:  "geometric lines"—and/or: "geometric line segments"—we are asked to:  
  "Find the value of:  " AB and BC" .
    {<u>Given</u>: " <em>AB</em> = (8x + 3) ;  <em>BC  </em>= (2x + 7) ;  <em>AC </em>= 80 ".}.
----------------------------------------------------------------------------------------------=-
<u>Note</u>:  The following "<u>line graphs</u>" are "<u>Not Drawn to Scale</u>."

           

        |    (8x + 3)     |      (2x + 7)       |

        |<--------------->|<------------------->|

<----·|----------------->|<------------------->|  {<u>Note</u>:  "Not drawn to scale."}.
       A                   B                         C

<-----|----------------->|<------------------->|

       A                                               C

<-----|<--------------------------------------->|  

<-----|----------------------------------------->|          

       A             {"<em>AC</em> = 80 ".}             C

         

 <---|------------------------------------------>|
       A       {"
<em>AC</em><em> </em>= 80 ".}.                  C

       |  (8x + 3) ;   +       (2x + 7)      =  80 ;  

<-----|----------------->|<--------------------->I
       A                    B                         C


So:  
We have to find the value of:
     1) <em>AB </em>; which is: (8x + 3) ;  <u>And:</u>
     2) <em>BC </em>;  which is:  (2x + 7) .

To get these values; we need to find the value for "x".

So:   (8x + 3)  +  (2x + 7)   = 80  ;  
      ➝  8x + 3 + 2x + 7 = 80 ;

      ➝ Now, Let us combine the "like terms" on the "<u><em>left-hand side</em></u>" of the equation:
    +8x + 2x + 3 + 7  ;

      ➝  to get: + 8x + 2x = + 10x  ; <u><em>and:</em></u>
                       +3 + 7 = 10 ;

      To get:  "10x + 10" ;

Now, we can rewrite the equation:
       {" 70 ÷ 10 = 7 ."}.   " 10x + 10 = 80 ;

_____________________
To solve for "x" ; there are many ways:
_____________________
Method 1)  We have:  " 10x + 10 = 80 " ;
 ➝ Now, subtract "10" from each side of the question;
       10x + 10 − 10 = 80 − 10 ;
to get:  10x = 70 ;

 ➝  Now, divide each side of the equation by: "10" ; to isolate "x" on one side of the equation;  & to solve for "x" ;

  10x /10 = 70 /10 ;   to get:  " x = 7 "

Method 2)
 At the moment above in which we have:
" 10x = 70 " ;   we know that "10x ÷ 10 = 1x" ; and then "70 ÷ 10 = 7 ".

       {<u>Note that any value; divided by "</u><u>10"</u> ;  is equal to:
{"that value" moved Back by:  "One" decimal space.}.  

So:  " 1x = 7 " ; ↔ " x = 7 ".

_____________
Method 3) :

When we have:  " 10x /10 = 70 /10 " ;  we have " 1x " on the "<u>left-hand side</u>" of the equation;  <u><em>and:</em></u>  "{ 70 /10 }" = {" 70 ÷ 10 = 7 ."}.

Note that: {" 70 ÷ 10 = 7 "} ; can be determined in many ways;
    For instance: {" 70 ÷ 10 = <u> ? </u>"} ;  

 ➝  The zeros for Both the numerator <u><em>and</em></u> denominator "cancel out"—

and we have:  " \frac{70}{10} " ;  
 ➝  Cancel out each of the two (2) "zeros" ; and we have:  " \frac{7}{1} = 7. "

 ➝  This is assuming that we figure out that:  " \frac{10x}{10}=1x =x ."

___________

<u>Now; let's find the correct values for this Brainly Question</u>:
1)
<em>AB  </em>=  8x + 3 ;  
Substitute our calculated value for "x" ; and solve:

➝  <em>AB </em><em> </em>= 8x + 3 ;  ↔  8(7)  + 3   =  56  + 3  = 59 .

➝ <em>BC  </em>= 2x + 7 ;  ↔ 2(7)  +  7   =  14 + 7   =  21 .<em>
</em><u>Note</u>:
➝  <em>AC</em>  =  80 = <em>AB</em>  + BC   ≟   59 + 21  ≟  80 ?  Yes!

____________
Answers:
 1) The value of <em>AB</em>  is:  " 59 units."
 ___
 2) The value of <em>BC</em>  is:   "21 units."
___

 3) The value of <em>AB</em> + <em>BC</em>  ;

           = 59 units + 21 units  =  {<u>The value of </u><u><em>AC</em></u><em> </em><u>}</u>  =  "80 units".}.

_____
Hope this answer—along with explanations—is helpful to you.

  Best wishes in your academic pursuits!

______

7 0
2 years ago
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