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3 years ago

Can someone help me with this maths question

Mathematics

1 answer:

vazorg [7]3 years ago

4 0

https://www.force11.org/event/watch-england-vs-south-africa-live-stream-watch-rugby-friendly-3rd-nov

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The figures are similar. The ratio of the perimeters is 8 : 5. Find X

vova2212 [387]

Answer:

Two figures that have the same shape are said to be similar. When two figures are similar, the ratios of the lengths of their corresponding sides are equal. To determine if the triangles below are similar, compare their corresponding sides.

3 0

3 years ago

Help please I need an answer for this fast

castortr0y [4]

Answer:

B 9, -9

Step-by-step explanation:

x^2 - 81 = 0

Add 81 to each side

x^2 = 81

Take the square root of each side

sqrt(x^2) = sqrt(81)

x = ±9

6 0

2 years ago

Write an expression that is equivalent to 123x + x + 2x

Svetlanka [38]

This simplified is 126x so that is equivalent to this expression

7 0

3 years ago

How to factor a trinomial x^2+11x+19

Tresset [83]

Answer:

this trinomial is prime, and cannot be factored.

Step-by-step explanation:

when expanding the equation, you multiply the last term by the first term's coefficient, and then find two factors that multiply to that product, and sum to the middle coefficient.

1 * 19 = 19

there are no factors that will multiply to 19 and sum to 11. thus, this polynomial is prime.

4 0

3 years ago

-/2 points

Rom4ik [11]

Answer:

Part 1) The domain of the quadratic function is the interval (-∞,∞)

Part 2) The range is the interval (-∞,1]

Step-by-step explanation:

we have

$f(x)=-x^2+14x-48$

This is a quadratic equation (vertical parabola) open downward (the leading coefficient is negative)

step 1

Find the domain

The domain of a function is the set of all possible values of x

The domain of the quadratic function is the interval

(-∞,∞)

All real numbers

step 2

Find the range

The range of a function is the complete set of all possible resulting values of y, after we have substituted the domain.

we have a vertical parabola open downward

The vertex is a maximum

Let

(h,k) the vertex of the parabola

The range is the interval

(-∞,k]

Find the vertex

$f(x)=-x^2+14x-48$

Factor -1 the leading coefficient

$f(x)=-(x^2-14x)-48$

Complete the square

$f(x)=-(x^2-14x+49)-48+49$

$f(x)=-(x^2-14x+49)+1$

Rewrite as perfect squares

$f(x)=-(x-7)^2+1$

The vertex is the point (7,1)

therefore

The range is the interval

(-∞,1]

6 0

3 years ago