2 years ago

Can someone help me with this maths question

Mathematics

1 answer:

vazorg [7]2 years ago

4 0

https://www.force11.org/event/watch-england-vs-south-africa-live-stream-watch-rugby-friendly-3rd-nov

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-5(x + 1) = -3(2x - 2)

kicyunya [14]

Answer:

x=11

Step-by-step explanation:

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2 years ago

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23,000,022 = 1<br> use the operation symbole

daser333 [38]

291-2999=10376 square feet

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2 years ago

Find <img src="https://tex.z-dn.net/?f=%5Csqrt%7B144%7D" id="TexFormula1" title="\sqrt{144}" alt="\sqrt{144}" align="absmiddle"

Nikolay [14]

Answer:

Step-by-step explanation:

The square root of 144 = 12.

12 x 12 = 144

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2 years ago

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Resistors are labeled 100 Ω. In fact, the actual resistances are uniformly distributed on the interval (95, 103). Find the mean

Zinaida [17]

Answer:

$E[R]$ = 99 Ω

$\sigma_R$ = 2.3094 Ω

P(98<R<102) = 0.5696

Step-by-step explanation:

The mean resistance is the average of edge values of interval.

Hence,

The mean resistance, $E[R] = \frac{a+b}{2} = \frac{95+103}{2} = \frac{198}{2}$ = 99 Ω

To find the standard deviation of resistance, we need to find variance first.

$V(R) = \frac{(b-a)^2}{12} =\frac{(103-95)^2}{12} = 5.333$

Hence,

The standard deviation of resistance, $\sigma_R = \sqrt{V(R)} = \sqrt5.333$ = 2.3094 Ω

To calculate the probability that resistance is between 98 Ω and 102 Ω, we need to find Normal Distributions.

$z_1 = \frac{102-99}{2.3094} = 1.299$

$z_2 = \frac{98-99}{2.3094} = -0.433$

From the Z-table, P(98<R<102) = 0.9032 - 0.3336 = 0.5696

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3 years ago

Use the diagram of the right triangle above and round your answer to the nearest hundredth. If m <br> a. 17.32 m<br> b. 6.93 m<b

zepelin [54]

In ΔABC,
tanA = a/b
∴ a = b×tanA = 12×1/√3 = 6.928 ~ 6.93 m

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2 years ago