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Nookie1986 [14]
2 years ago
9

Treatment of Rhinophyma With Fractional CO2 Laser Resurfacing in a Woman of Color: Case Report and Review of the Literature

Biology
1 answer:
Westkost [7]2 years ago
7 0
<h3>What is Rhinophyma?</h3>
  • The lower two-thirds of the nose are erythematous, hypertrophied, and inflamed when someone has rhinophyma, a disfiguring condition.
  • Rhinophyma, which is frequently referred to as the severe version of acne rosacea, can cause functional, aesthetic, and psychosocial issues that call for cosmetic care.
  • Early detection and management are essential components of treatment for rosacea since doing so can prevent the condition from progressing to rhinophyma.
<h3>What is the first reported case of Rhinophyma?</h3>
  • The first incidence of rhinophyma to be documented in a 62-year-old Fitzpatrick V female patient, who underwent a single session of fractional carbon dioxide laser resurfacing with great success.
  • The efficacy of the fractional carbon dioxide laser in treating rhinophyma in patients with darker skin tones (Fitzpatrick IV–VI) is highlighted in this example
  • Underscoring the potential for its application in the treatment of patients of color in the future.

Learn more about cosmetic surgery here:

brainly.com/question/1740878

#SPJ4

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In tropical climates, why is there heavy vegetation but poor soil?
Georgia [21]
Answer - B

Reason - Since the area is in the tropics there will be time to time heavy precipitation, which over time the decomposed nutrients will get washed down into a run off and depleted.
5 0
3 years ago
1 and 2 please i dont know the answers i have more to come
bixtya [17]

Answer:

1. C.) Their cell walls contain chitin

2. C.) Chloroplast

4 0
3 years ago
In a population of cats, the phenotypic frequency of black cats is 91%, and the phenotypic frequency of white cats is 9%. Assumi
Talja [164]

Answer:

1. Allele frequency of b = 0.09 (or 9%)

2. Allele frequency of B = 0.91 (0.91%)

3. Genotype frequency of BB = 0.8281 (or 82.81%)

4. Genotype frequency of Bb = 0.1638 (or 16.38%)

Explanation:

Given that:

p = the frequency of the dominant allele (represented here by B)  = 0.91

q = the frequency of the recessive allele (represented here by b)  = 0.09

For a population in genetic equilibrium:

p + q = 1.0 (The sum of the frequencies of both alleles is 100%.)

(p + q)^2 = 1

Therefore:

p^2 + 2pq + q^2 = 1

in which:  

p^2 = frequency of BB (homozygous dominant)

2pq = frequency of Bb (heterozygous)

q^2 = frequency of bb (homozygous recessive)

p^2 = 0.91^2 = 0.8281

2pq = 2(0.91)(0.9) = 0.1638

4 0
3 years ago
Where does the sedimentary rock chalk form? from the precipitation of minerals in shallow marine environments by the lithificati
Katarina [22]

The correct answer is an accumulation of microorganisms in deep marine environments.

Chalk rock refers to a pure form of limestone produced in tropical and warm seas about 100 million years ago in the Cretaceous period. The microscopic marine algae known as coccoliths thrived in the ancient seas. Their shells were comprised of calcite. With the death of the algae, their bodies sunk to the floor of the sea and sediment of chalk got deposited.

Over many years layers of chalk sediment got deposited and resulted in compaction of loose sediment into solid chalk rock.

8 0
3 years ago
Recall that two hydrogen bonds bind A and T, but three hydrogen bonds bind G and C. Because the
tensa zangetsu [6.8K]

Answer:

C

Explanation:

7 0
3 years ago
Read 2 more answers
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