The friction force has a 2 N force.
The static friction coefficient that exists between the project and the surface should be multiplied to provide the friction force. When the surface is thought of as horizontal, the normal force should be equal to the weight of the block and should also be directed in the opposite direction.
the friction force is therefore
= 0.5*N = 0.5* (10)
= 5
The friction force is greater than the force acting on the block, which is why there is no movement of the object even though it should be the reverse. Furthermore, the actual force needs to be equal.
The friction force here should therefore be 2N.
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A 2.0-N force acts horizontally on a 10-N block that is initially at rest on a horizontal surface. The coefficient of static friction between the block and the surface is 0.50. What is the magnitude of the frictional force that acts on the block?
