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marshall27 [118]
2 years ago
14

figure shows four situations in which a horizontal net force acts on the same block which is initially at rest

Physics
1 answer:
skelet666 [1.2K]2 years ago
3 0

The friction force has a 2 N force.

The static friction coefficient that exists between the project and the surface should be multiplied to provide the friction force. When the surface is thought of as horizontal, the normal force should be equal to the weight of the block and should also be directed in the opposite direction.

the friction force is therefore

= 0.5*N = 0.5* (10)

= 5

The friction force is greater than the force acting on the block, which is why there is no movement of the object even though it should be the reverse. Furthermore, the actual force needs to be equal.

The friction force here should therefore be 2N.

Learn more about force here: brainly.com/question/4241156

#SPJ4

A 2.0-N force acts horizontally on a 10-N block that is initially at rest on a horizontal surface. The coefficient of static friction between the block and the surface is 0.50. What is the magnitude of the frictional force that acts on the block?

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So a Shuttle that weighed 20 million Newtons on the launch pad weighed roughly  17 million Newtons while in orbit.


4 0
3 years ago
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A dolphin in an aquatic show jumps straight up out of the water at a velocity of 13.0 m/s.
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Answer:

a) Knowns, initial speed v_{i}=13.0 m/s, final speed v_{f}=0 m/s and gravity due it is a constant g=9.8m/s^{2}

b) The maximum high reached by the dolphin is y_{max}=8.62 m

c) Total time is t=2.65s

Explanation:

a) First of all the initial speed is given at the start of the problem, gravity is constant and final speed is known any object thrown straight up reaches its max high at 0m/s speed.

b) Second, now that we know final speed we use v_{f} =v_{i}-gt, as we clear for t=\frac{v_{i}-v_{f} }{g}=\frac{20.0m/s}{9.8m/s^{2} }=1.32 s.

Then we use y=v_{i}t-\frac{1}{2} gt^{2}=(20.0m/s)(1.32s)-\frac{1}{2} (9.8m/s^{2} ) (1.32s)^{2}  =8.62m

c)Third, finally we can use y=v_{i}t-\frac{1}{2} gt^{2}, as we know y=0m when the dolphin fall into the water again and v_{i} =13.0m/s, then we have 0=(13m/s)t-\frac{1}{2} (9.8m/s^{2}  )t^{2} is a quadratic form 0=t(13.0-4.9t) so we have t_{i}=0s and t_{f}=\frac{13}{4.90}  =2.65s

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<u>Non-Uniform motion</u>: When unequal amount of distance is covered in equal intervals of time.

Motion can be of the following types as well:

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Thus, in order to define motion, only two variables are required: position and time. Measuring these variables can determine whether the object is in motion or not and the type of motion.

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3 years ago
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Answer:

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Explanation:

The change in between the starting position (initial position) and your final position is the amount of distance you <em>actually </em>traveled.

For example, you can use a triangle. The distance you travel for side length a  & b is equal to the distance you travel on side c (the hypotenuse). You are pretty much solving for the hypotenuse in this case, or the displacement.

~

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