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kompoz [17]
3 years ago
14

What systems are responsible for moving the gases oxygen and carbon dioxide?

Chemistry
1 answer:
uranmaximum [27]3 years ago
6 0
Humans (people) what ever way u put it that's ur answer
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I need help with this question. Thank you.
marishachu [46]
There are 76 atoms in total
3 0
3 years ago
Ascorbic acid, or vitamin C (C6H8O6, molar mass = 176 g/mol), is a naturally occurring organic compound with antioxidant propert
Rus_ich [418]

Answer:

The quantity of ascorbic acid found in sweet lime of 49.6 mg does not meet the daily requirement.

Explanation:

To determine the mass of ascorbic acid knowing the number of moles we use the following formula:

number of moles = mass / molecular weight

mass = number of moles × molecular weight

mass of ascorbic acid = 2.82 × 10⁻⁴ × 176

mass of ascorbic acid = 496 × 10⁻⁴ g = 0.0496 g = 49.6 mg

daily requirement of ascorbic acid = 70 - 90 mg

The quantity of ascorbic acid found in sweet lime of 49.6 mg does not meet the daily requirement.

6 0
3 years ago
Read 2 more answers
NOT A TEST AND I WILL GIVE BRAINLEIST DON'T ANSWER IF YOU DON'T KNOW
barxatty [35]

Answer:

In the nucleus of an atom ,there are protons & neutrons. Protons have charge of 1.6× 10^-19 C, while neutrons have 0C charges. Electrons orbit outside the atom. Their charge is - 1.6 ×10^-19C

Explanation:

5 0
3 years ago
Which substance has the highest viscosity?
Lemur [1.5K]
Room temperature has the highest viscosity
6 0
3 years ago
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A 0.5376 g sample of an unknown compound is found to contain 0.3044 g of carbonate. Could this compound be calcium carbonate?
shepuryov [24]
Calcium carbonate has the formula: CaCO3
From the periodic table:
mass of calcium = 40 grams
mass of carbon = 12 grams
mass of oxygen = 16 grams
Therefore,
molar mass of CaCO3 = 40 + 12 + 3(16) = 100 grams
molar mass of carbonate = 12 + 3(16) = 60 grams

One mole of calcium carbonate contains one mole of carbonate. Therefore, 100 grams of CaCO3 contains 60 grams of CO3.
If the 0.5376 grams of the unknown substance is CaCO3, then the amount of carbonate will be:
amount of carbonate = (0.5376*60) / 100 = 0.32256 grams

Based on the above calculations, the sample is not CaCO3
6 0
3 years ago
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