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Anvisha [2.4K]
3 years ago
10

18 grams 4 kilograms 8 kilograms

Chemistry
1 answer:
Rina8888 [55]3 years ago
5 0

Answer:

1 18 grams

2 500g

4 960 grams

5 7 kilograms

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they are:-

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orfice plate.

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pitot tube.

Averaging pitot tube .

cone meter.

linear resis meter.

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2 years ago
What is a common reason for observing an increased chemical shift of a c-h proton
stira [4]

Deshielding due to an electronegative element close by is the common reason for observing increased chemical shift of a c-h proton

<h3>What is a chemical shift? </h3>

The resonance frequency of a proton in relation to a standard compound is represented by chemical shift. Chemical shift, which is measured in ppm and is represented by the sign (δ),  (parts per million).The chemical shift in a proton NMR spectrum provides details about the targeted proton's chemical surroundings. The structure of the investigated substance, especially electronegative components or effects, has a significant impact on the chemical shift value. Electronegative elements' ability to remove electron density from the proton, which raises the chemical shift value, is one explanation for this. The proton is more exposed to the magnetic field that is being applied externally as a result of this process, which is referred to as de-shielding.

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3 0
2 years ago
Balanced chemical equation for the standard formation reaction of solid sodium carbonate
kenny6666 [7]
CO2 + 2 NaOH → Na2CO3 + H2O
4 0
3 years ago
Read 2 more answers
(more then one answer) As a form of energy, light has specific properties such as color and brightness. Some properties can only
Lelu [443]

Answer:

Light travels in a straight line until it strikes an object.

As white light passes through a prism , it bends and separates into different colors

3 0
3 years ago
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A sample of a compound is decomposed in the laboratory and produces 330 g carbon, 69.5 g hydrogen, and 220.2 g oxygen. Calculate
Zarrin [17]

Answer: Empirical formula is C_2H_5O

Explanation: We are given the masses of elements present in a sample of compound. To evaluate empirical formula, we will be following some steps.

<u>Step 1 :</u> Converting each of the given masses into their moles by dividing them by Molar masses.

Moles=\frac{\text{Given mass}}{\text{Molar mass}}

Molar mass of Carbon = 12.0 g/mol

Molar mass of Hydrogen = 1.0 g/mol

Molar mass of Oxygen = 16.0 g/mol

Moles of Carbon = \frac{330g}{12g/mol}=27.5moles

Moles of Hydrogen = \frac{69.5g}{1g/mol}=69.5moles

Moles of Oxygen = \frac{220.2g}{16g/mol}=13.76moles

<u>Step 2: </u>Dividing each mole value by the smallest number of moles calculated above and rounding it off to the nearest whole number value

Smallest number of moles = 13.76 moles

\text{Mole ratio of Carbon}=\frac{27.5moles}{13.76moles}=1.99\approx 2

\text{Mole ratio of Hydrogen}=\frac{69.5moles}{13.76moles}=5.05\approx 5

\text{Mole ratio of Oxygen}=\frac{13.76moles}{13.76moles}=1

<u>Step 3:</u> Now, the moles ratio of the elements are represented by the subscripts in the empirical formula

Empirical formula becomes = C_2H_5O

7 0
3 years ago
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