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Klio2033 [76]
3 years ago
6

A single replacement reaction is a reaction in which one element replaces a similar element within a compound. True False

Chemistry
2 answers:
Andru [333]3 years ago
6 0

Answer:

true

Explanation:

the people above is correct

NNADVOKAT [17]3 years ago
3 0

Answer:

True

Explanation:

In a single replacement reaction, one element is replacing a similar element within a given compound.

For example;

       A  + BC → AC + B

The replacement of a metallic ion in solution by a metal ion higher in the activity series than the metal in solution falls into this category of reactions.

The relative position of the two elements in the activity series provides the driving force for the single replacement reactions.

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Carbon, helium, and sodium are monoatomic elements.

Hydrogen, iodine, and oxygen are diatomic elements.
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Of the molecules below, the bond in __________ is the most polar. hbr hi hcl hf
Black_prince [1.1K]
<span>There's a trend in electronegativity. The bottom left of periodic table is the lowest (0.7) and the upper right is the highest (4.0). The most polar is the greatest difference in electronegavity. hbr- 1~ , hi- 0.5~ ,hcl - 1.3~ , hf-1.8 so,hf is the answer</span>
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Identify the half reaction as oxidation or reduction.
topjm [15]
OILRIG:
Oxidation is loss (of electrons)
Reduction is gain (of electrons)
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3 years ago
A synthesis reaction takes place when carbon monoxide (CO) and hydrogen gas (H2) react to form methanol (CH3OH). How many grams
kakasveta [241]

Answer:

A. 3.2grams

Explanation:

First we need to get the chemical equation for this reaction:

CO + H₂ → CH₃OH

We then need to balance the equation:

CO + <u>2</u>H₂ → CH₃OH

Our next step is to first convert our given into moles. We do this by figuring out first how many grams of each substance there are in 1 mole by adding up the atomic mass of each element in each substance.

             Carbon(1)       Oxygen(1)

CO =       12.011(1)      +   15.999(1)   = 28.01 g/mole

            Hydrogen(2)

H₂ =        1.008(2)        =  2.016g/mole

We can then use this to determine how many moles of each reactant we have given the mass.

CO = 2.8g\\2.8g\times\dfrac{1mole}{28.01g}=0.1moles\\\\H_{2}=0.50g\\\\0.50g\times\dfrac{1mole}{2.016g}=0.469moles

So here we have our new given:

0.1 moles of CO

0.496 moles of H₂

We then need to determine how much product we produce with our given.

According to our chemical equation we can assume that:

For every 1 mole of CO we can produce 1 mole of CH₃OH

Fore every 2 moles of H₂ we can produce 1 mole of CH₃OH

Using this ratio we can determine how much product each reactant will produce by using the ratios:

0.1 moles of CO\times\dfrac{1moleofCH_{3}OH}{1moleofCO}=0.1moles of CH_{3}OH\\\\ 0.496molesofH_{2}\times\dfrac{1moleofCH_{3}OH}{2molesofH_{2}}=0.248molesofCH_{3}OH

Now notice that they are not equal. The reactant that produces the least amount of product will be our limiting reactant. The limiting reactant determines the amount of product that is produced, because once it is completely used up, the reaction stops. So in this case, the amount of CH₃OH that is produced is 0.10 moles.

Now we need to figure out how many this is in grams. To do that we need to find out how many grams of CH₃OH there are in 1 mole of CH₃OH.

                   Carbon (1)             Hydrogen(4)          Oxygen(1)

CH₃OH =      12.001(1)     +           1.008(4)       +       15.999(1)

            =      12.001         +           4.032          +        15.999     = 32.032g/mole

We then use this for converting:

0.10 moles\times\dfrac{32.032g}{1mole}=3.2032g

So the reaction will produce 3.2032g of CH₃OH or 3.2g of CH₃OH

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kirill115 [55]

I think that this is

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