1.1 / 2 = .7 --> 2.86 yrs
.7 / 2 = .45 —> 5.72 yrs
.45 / 2 = .225 —> 8.58 yrs
.225 / 2 = .1125 —> 11.44 yrs
So, for the sample of plutonium to reach .140 mg it should take a little less than 11.44 years.
Hope this helps
<h3>
Answer:</h3>
5.6 L
<h3>
Explanation:</h3>
We are given;
- Initial volume, V1 = 3.5 L
- Initial pressure, P1 = 0.8 atm
- Final pressure, P2 = 0.5 atm
We are required to calculate the final volume;
- According to Boyle's law, the volume of a fixed mass of a gas and the pressure are inversely proportional at a constant temperature.
- That is; P α 1/V
- Mathematically, P=k/V
- At two different pressure and volume;
P1V1 = P2V2
In this case;
Rearranging the formula;
V2 = P1V1 ÷ P2
= (0.8 atm × 3.5 L) ÷ 0.5 atm
= 5.6 L
Therefore, the resulting volume is 5.6 L
Complete Question
A marine biologist is preparing a deep-sea submersible for a dive. The sub stores breathing air under high pressure in a spherical air tank that measures 74.0 wide. The biologist estimates she will need 2600 L of air for the dive. Calculate the pressure to which this volume of air must be compressed in order to fit into the air tank. Write your answer in atmospheres. Round your answer to significant digits.
Answer:
The pressure required is 
Explanation:
Generally the volume of a sphere is mathematically denoted as

Substituting 


Converting to Liters


Assume that the pressure at which the air is given to the diver is 1 atm when the air was occupying a volume of 2600L
So
From Charles law

Substituting
,
,
, and making
the subject we have



The way scientists form a hypothesis is there is something called the scientific method. You established your question or problem first. Then you research it. You take your hypothesis, theory, or prediction of what is going to happen from your research.
Answer:
2.4 dm-3
Explanation:
Equation of the reaction;
2HCl(aq) + Ba(OH)2(aq) -------> BaCl2(aq) + 2 H2O(l)
Volume of acid VA = ??
Concentration of acid CA = 0.25 moldm-3
Volume of base VB = 2.0 dm^3
Concentration of base CB = 0.15 moldm-3
Number of moles of acid NA = 2
Number of moles of base NB = 1
CAVA/CBVB = NA/NB
CAVANB = CBVBNA
VA = CBVBNA/CANB
VA = 0.15 * 2 * 2/0.25 *1
VA = 2.4 dm-3